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3 years ago

What claim can you make about the relationship between energy and mass?

1 answer:

3 0

In physics mass-energy equivalence is the principal that anything having mass has an equivalent amount of energy and vise versa.

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Tim’s cow is anemic. The cow is lacking which type of nutrient?

mixer [17]

Answer:

Iron deficiency

Explanation:

or more scientifically explained as decreased hemoglobin levels in your blood but still caused by lack of iron.

6 0

3 years ago

Read 2 more answers

Tina's calculations of the tarantula found that the spider was able to cover 20 centimeters in five seconds what was the average

Sergeu [11.5K]

<span>(20 cm)/(5 sec) = (0.20 meters)/(5 seconds)
</span>

8 0

4 years ago

How will the force of friction affect a wood block being pushed over a table?

olasank [31]

Answer:

friction acts in the opposite direction of motion but does not affect the motion of the object

5 0

2 years ago

An artificial satellite is in a circular orbit around a planet of radius r= 2.05 x103 km at a distance d 310.0 km from the plane

lubasha [3.4K]

Answer:

$\rho = 12580.7 kg/m^3$

Explanation:

As we know that the satellite revolves around the planet then the centripetal force for the satellite is due to gravitational attraction force of the planet

So here we will have

$F = \frac{GMm}{(r + h)^2}$

here we have

$F =\frac {mv^2}{(r+ h)}$

$\frac{mv^2}{r + h} = \frac{GMm}{(r + h)^2}$

here we have

$v = \sqrt{\frac{GM}{(r + h)}}$

now we can find time period as

$T = \frac{2\pi (r + h)}{v}$

$T = \frac{2\pi (2.05 \times 10^6 + 310 \times 10^3)}{\sqrt{\frac{GM}{(r + h)}}}$

$1.15 \times 3600 = \frac{2\pi (2.05 \times 10^6 + 310 \times 10^3)}{\sqrt{\frac{(6.67 \times 10^{-11})(M)}{(2.05 \times 10^6 + 310 \times 10^3)}}}$

$M = 4.54 \times 10^{23} kg$

Now the density is given as

$\rho = \frac{M}{\frac{4}{3}\pi r^3}$

$\rho = \frac{4.54 \times 10^{23}}{\frac{4}[3}\pi(2.05 \times 10^6)^3}$

$\rho = 12580.7 kg/m^3$

8 0

3 years ago

The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 23

Burka [1]

Answer:

a) $v(2) = 3.9\,\frac{m}{s}$ , b) $v(4) = -15.7\,\frac{m}{s}$

Explanation:

a) The equation for vertical velocity is obtained by deriving the function with respect to time:

$v(t) = 23.5 -9.8\cdot t$

The velocities at given instants are, respectivelly:

$v(2) = 3.9\,\frac{m}{s}$

$v(4) = -15.7\,\frac{m}{s}$

8 0

3 years ago

What claim can you make about the relationship between energy and mass?​

What claim can you make about the relationship between energy and mass?