What claim can you make about the relationship between energy and mass?

Given your choice for part 1, would it be possible, in principle under ideal circumstances, for a balloon to stick to a wall ind

podryga [215]

Answer:

Explanation:1)Rub a balloon on your head and stick it to the wall. And it sticks—very nice. We’ve

talked in lecture about why it sticks. This question is about why, after a while, it fall off.

Consider each of the following explanations.

i) It falls because it uses up the energy you put on it when you rubbed it.

ii) It falls because it uses up the charge you put on it when you rubbed it.

iii) It falls because the energy you put on it slowly leaks off into the wall or the air.

iv) It falls because the charge you put on it slowly leaks off into the wall or the air.

Answer: It falls because the charge you put on it slowly leaks off into the wall or the air.

2) Given your choice for part a, would it be possible, in principle under ideal

circumstances, for a balloon to stick to a wall indefinitely?

Answer: If you can keep the charge from leaving the balloon, And if the

wall is a very good insulator also this will prevent the ball from falling.

8 0

3 years ago

Using the experimentally determined resonant frequency and measured value of the capacitor, find the value of the inductor. 4. d

mafiozo [28]

2.496 HZ is the resistance change the resonant frequency.

Given, Supply frequency, f = 60 12

number of poles, P = 4

Full load speed, Ne= 1725 rpm

Synchronous speed; No= 1201= 120X60 = 1800 rpm

P

4

We know the formula for Full load-speed

Ne = N's (1 - Sf)

where se = full load rotor ship

Ne = 1 - SP

SQ = 1- Ne = 1- 1725 = 0.0416 DY 4-16%

1800

SQ= 4. 16 % or 0.0416

Frequency of rotor, fy= Sgif = (0.0416) ( 60 ) = 2.496 Hz

fr = 2.496 HZ

Learn more about Frequency here: brainly.com/question/16148316

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8 0

2 years ago

A 10 kg dog runs across the ground and jumps onto an ice-covered pond at 5 m/s. If the force of friction acting on the dog is 8

zzz [600]

Answer:

15.625m

Explanation:

Using the equation of motion

v² = u²+2as

u and v are the initial and final velocities

a is the acceleration

s is the distance

Get the acceleration

According to Newton's second law;

F = ma

8 = 10a

a = 8/10

a = 0.8m/s²

We are also given

v = 5m/s

u = 0m/s

Substitute into the formula above

v² = u²+2as

5² = 0²+2(0.8)s

25 = 1.6s

s = 25/1.6

s = 15.625m

Hence the dog will cover a distance of 15.625m before coming to rest

3 0

3 years ago

If the reading of a linear scale is 4 mm and no of division of the circular scale is 50, then what will be the diameter of the w

Sliva [168]

Answer:

Diameter of Wire = 4.5 mm

Explanation:

First, we need to find the fractional part of the reading. The fractional part o the reading can be given by the following formula:

Fractional Part = Circular Scale Reading x Least Count

where,

Circular Scale Reading = 50

Least Count = 0.01 mm

Therefore,

Fractional Part = (50)(0.01 mm)

Fractional Part = 0.5 mm

Now, the diameter of the wire can be given by using the following formula:

Diameter of Wire = Linear Scale Reading + Fractional Part

Diameter of Wire = 4 mm + 0.5 mm

<u>Diameter of Wire = 4.5 mm</u>

8 0

3 years ago

Two points are located on a rigid wheel that is rotating with decreasing angular velocity about a fixed axis. Point A is located

Norma-Jean [14]

d.Both points have the same instantaneous angular velocity.

Explanation:

Let's analyze each option one by one:

a.the angular velocity at point A is greater than that of point B. --> FALSE. In fact, for a rigid body (such as the rigid wheel in this problem), all the points along the body rotates with the same angular velocity. This is because the angular velocity is defined as

$\omega=\frac{\theta}{t}$

where $\theta$ is the angular displacement and t is the time taken. Therefore, all the points rotate by the same angle $\theta$ in the same time t.

b.Both points have the same centripetal acceleration. --> FALSE. The centripetal acceleration of a point along the disk is given by

$a_c=\omega^2 r$

where $\omega$ is the angular velocity and r is the distance of the point from the axis of rotation. Here A is located farther away from the axis with respect to B, so it will have a greater centripetal acceleration.

c.Both points have the same tangential acceleration. --> FALSE. The tangential acceleration is given by

$a_t = \alpha r$

where $\alpha$ is the angular acceleration. $\alpha$ is the same for every point for a rigid body, but $r$ is not (A is located farther away), so A and B do not have same tangential acceleration.

d.Both points have the same instantaneous angular velocity. --> TRUE. This is true for what we said at point A).

e.Each second, point A turns through a greater angle than point B. --> FALSE. The two points cover the same angular displacement in the same time, since they have same angular velocity.

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

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4 0

4 years ago

What claim can you make about the relationship between energy and mass?​

What claim can you make about the relationship between energy and mass?