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son4ous [18]
2 years ago
10

Which of the objects have only potential energy?

Physics
1 answer:
vitfil [10]2 years ago
4 0

Answer:

A raised weight.

Water that is behind a dam.

A car that is parked at the top of a hill.

A yoyo before it is released.

River water at the top of a waterfall.

A book on a table before it falls.

A child at the top of a slide.

Ripe fruit before it falls.

Explanation:

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French fries were on your car
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In a certain region of space near earth's surface, a uniform horizontal magnetic field of magnitude B exists above a level defin
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Answer:

a) F = \frac{\pi d^2B^2lv}{16p}  

b) attached below

c) 0.037 m/s

Explanation:

<u>a) Determine the magnetic "drag" force acting  at the moment </u>

speed = v

first step: determine current in the loop

I = \frac{\pi d^2}{16pl} B lv   ----- ( 1 )

given that the current will induce force on the three sides of the loop found in the magnetic field

forces on vertical sides = + opposite

we will cancel out

hence equation 1 becomes

F = \frac{\pi d^2B^2lv}{16p}   ( according to Lenz law we can say that the direction of force is upwards and this force will slow down the decrease in flux )

<u>b) Determine the formula for Vt</u>

attached below

<u>c) Find Vt </u>

given :

B = 0.80 T

density of copper = 8.9 * 10^3 kg/m^3

resistivity of copper = 1.68 * 10^-8 Ωm

∴ Vt = 16 ( 8.9 * 10^3 kg/m^3 ) ( 1.68 * 10^-8 Ωm ) ( 9.8 m/s^2 ) / ( 0.08 T)^2

       = 0.037 m/s

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A force exerted on an object produces acceleration. If the mass remains the same and the acceleration is doubled, the force must
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If both the net force and the mass are doubled, the acceleration will be unchanged.

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A pendulum is moving 2.0 m/s at the bottom of its swing. How high vertically will it go before it begins to swing back? Group of
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Answer:

h = 0.2 m

Explanation:

Given that,

A pendulum is moving 2.0 m/s at the bottom of its swing.

We need to find the height high it swing back. Let the height is h.

Using the conservation of energy such that,

\dfrac{1}{2}mv^2=mgh\\\\h=\dfrac{v^2}{2g}

Put all the values,

h=\dfrac{(2)^2}{2\times 10}\\\\h=0.2\ m

So, it will reach to a height of 0.2 m.

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