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Nata [24]
3 years ago
10

Two points are located on a rigid wheel that is rotating with decreasing angular velocity about a fixed axis. Point A is located

in the rim of the wheel and pint B is halfway between the rim and the axis. Which one of the following statements concerning this situation is true?
a.the angular velocity at point A is greater than that of point B.
b.Both points have the same centripetal acceleration.
c.Both points have the same tangential acceleration.
d.Both points have the same instantaneous angular velocity.
e.Each second, point A turns through a greater angle than point B.
Physics
1 answer:
Norma-Jean [14]3 years ago
4 0

d.Both points have the same instantaneous angular velocity.

Explanation:

Let's analyze each option one by one:

a.the angular velocity at point A is greater than that of point B.  --> FALSE. In fact, for a rigid body (such as the rigid wheel in this problem), all the points along the body rotates with the same angular velocity. This is because the angular velocity is defined as

\omega=\frac{\theta}{t}

where \theta is the angular displacement and t is the time taken. Therefore, all the points rotate by the same angle \theta in the same time t.

b.Both points have the same centripetal acceleration.  --> FALSE. The centripetal acceleration of a point along the disk is given by

a_c=\omega^2 r

where \omega is the angular velocity and r is the distance of the point from the axis of rotation. Here A is located farther away from the axis with respect to B, so it will have a greater centripetal acceleration.

c.Both points have the same tangential acceleration.  --> FALSE. The tangential acceleration is given by

a_t = \alpha r

where \alpha is the angular acceleration. \alpha is the same for every point for a rigid body, but r is not (A is located farther away), so A and B do not have same tangential acceleration.

d.Both points have the same instantaneous angular velocity.  --> TRUE. This is true for what we said at point A).

e.Each second, point A turns through a greater angle than point B. --> FALSE. The two points cover the same angular displacement in the same time, since they have same angular velocity.

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

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SVETLANKA909090 [29]

Explanation:

For example, when a drum is struck, the flexible skin (sometimes called a membrane) of the drum vibrates. The compression and expansion of the air on either side of the vibrating membrane produces differences in air pressure. The pressure differences generate a sound wave that propagates outward from the drum surface.

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A fixed system of charges exerts a force of magnitude 22 N on a 4.0 C charge. The 4.0 C charge is replaced with a 8.0 C charge.
Karo-lina-s [1.5K]

Answer:

44 N

Explanation:

The electrostatic forces between two charges is given by:

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is their separation

We notice that the force is directly proportional to the charges.

In this problem, initially we have a force of

F = 22 N

on a q2 = 4.0 C, exerted by a charge q1.

If the charge is doubled,

q2 = 8.0 C

This means that the force will also double, so it will be

F=22 N \cdot 2 = 44 N

3 0
3 years ago
What happens to the gravitational attraction between 2 objects
amm1812

Answer:

It decreases.

Explanation:

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All living things are made up of two or more cells true or false
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Two long parallel wires 40 cm apart are carrying currents of 10 A and 20 A in the opposite direction. What is the magnitude of t
Alex_Xolod [135]

Answer:

The magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.

Explanation:

Given;

distance half way between the parallel wires, r = ¹/₂ (40 cm) = 20 cm = 0.2 m

current carried in opposite direction, I₁ and I₂ = 10 A and 20 A respectively

The magnitude of the magnetic field halfway between the wires can be calculated as;

B = \frac{\mu _oI_1}{2 \pi r} + \frac{\mu_oI_2}{2\pi r}

where;

B is magnitude of the magnetic field halfway between the wires

I₁ is current in the first wire

I₂ is current the second wire

μ₀ is permeability of free space

r is distance half way between the wires

B = \frac{\mu_o I_1}{2\pi r} + \frac{\mu_o I_2}{2\pi r} \\\\B = \frac{\mu_o }{2\pi r} (I_1 +I_2)\\\\B = \frac{4\pi *10^{-7} }{2\pi *0.2} (10 +20) = 3.0 *10^{-5}\  T

Therefore, the magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.

5 0
3 years ago
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