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Hatshy [7]
3 years ago
5

A coin rests on a record 0.13 m from its center. The record turns on a turntable that rotates at variable speed. The coefficient

of static friction between the coin and the record is 0.29. What is the maximum coin speed at which it does not slip?
Physics
1 answer:
igor_vitrenko [27]3 years ago
3 0

Answer:

Maximum speed of the coin, v = 0.607 m/s

Explanation:

It is given that,

A coin rests on a record 0.13 m from its center i.e. the radius of the circular path, r = 0.13 m

The coefficient of static friction between the coin and the record is, \mu=0.29

The centripetal force acting on the coin is balanced by the frictional force. Its mathematical relation is given by :

\dfrac{mv^2}{r}=\mu mg

v=\sqrt{\mu gr}

v=\sqrt{0.29\times 9.8\times 0.13}

v = 0.607 m/s

So, the maximum coin speed at which it does not slip is 0.607 m/s. Hence, this is the required solution.

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Answer:

λ= 5.24 × 10 ⁻² nC/cm

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Given:

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