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3 years ago

How many $10 bills are the same as one $100

Mathematics

1 answer:

Dmitry [639]3 years ago

7 0

Answer:

Step-by-step explanation:

10x10=100

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Evaluate the iterated integral. $$ \int\limits_0^{2\pi}\int\limits_0^y\int\limits_0^x {\color{red}9} \cos(x+y+z)\,dz\,dx\,dy $$

KengaRu [80]

$\displaystyle\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\int_{z=0}^{z=x}\cos(x+y+z)\,\mathrm dz\,\mathrm dx\,\mathrm dy=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(x+y+z)\bigg|_{z=0}^{z=x}\,\mathrm dx\,\mathrm dy$
$\displaystyle=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(2x+y)-\sin(x+y)\,\mathrm dx\,\mathrm dy$
$\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left(\cos(2x+y)-2\cos(x+y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dx\,\mathrm dy$
$\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left((\cos3y-2\cos2y)-(\cos y-2\cos y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dy$
$\displaystyle=-\frac12\int_{y=0}^{y=2\pi}(\cos3y-2\cos2y+\cos y)\,\mathrm dy$
$\displaystyle=-\frac12\left(\frac13\sin3y-\sin2y+\sin y\right)\bigg|_{y=0}^{y=2\pi}$
$=0$

4 0

3 years ago

9,10,11,and 12 please! Show work for all please!!!! Thanks! Please tell the answers as quick as possible

Vadim26 [7]

I'm not sure but I think I may have the answer to number 9
It says she uses 3 draws for shirts and wants to find out the percentage. Percentage is normally out of 100% so we do 100÷4 (we divide by 4 because there are 4 drawers)
100÷4=25. So now it says she uses three drawers for her shirts so we need to do 25x3=75 and all you do with that is put it in percent. The answer is 75%
P.S I am not entirely sure that this is correct but I wanted to help ❤

5 0

3 years ago

Help ASAP!!! Will give brainliest!!

lora16 [44]

Answer:

you have it tough what grade is this

Step-by-step explanation:

8 0

3 years ago

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7200 divided by y = 90

vladimir1956 [14]

Are you looking for y and if so y=80

3 0

3 years ago

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A polynomial has a leading coefficient of 1 and the

Hoochie [10]

Answer:

(A) $[x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}]$

Step-by-step explanation:

A polynomial has a leading coefficient of 1 and the following factors with multiplicity 1:

$x-(2+i)\\x-\sqrt{2}$

We apply the following to find the factored form of the polynomial.

If a complex number is a root of a polynomial with real coefficients, its complex conjugate is also a root of that polynomial.

If the polynomial has an irrational root $a+\sqrt{b}$ , where a and b are rational and b is not a perfect square, then it has also a conjugate root $a-\sqrt{b}$ .

$\text{Complex conjugate of }x-(2+i)=x-(2-i)\\\\\text{Complex conjugate of }x-\sqrt{2}=x+\sqrt{2}$

Therefore, the factored form of the polynomial is:

$[x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}]$

7 0

3 years ago

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