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Delicious77 [7]
3 years ago
8

3/4 is 60% of what number

Mathematics
1 answer:
Mariana [72]3 years ago
3 0
First change the fraction to percent. 
3/4 = 60%

Then change the percent to the decimal. 
60% = 0.75

Now multiply it.
<span>0.75 x 60% = 45
</span>
45 is the answer. 
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When the automobile manufacturer releases a new model in its WOW series, it promises that drivers can expect to get mlleage that
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28.4 divided by 6.5

Step-by-step explanation:

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Steve made $50 raking leaves and $75 mowing lawns he gave 60% of his earnings to his mother how much did Steve give to his mothe
bazaltina [42]

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Steve gave his mother $75.

Step-by-step explanation:

Steve earned a total of $125.  Sixty percent of that went to his mother.  Convert 60% into the equivalent decimal fraction and multiply as indicated:

0.60($125) = $75

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After how many audio books will both book clubs cost the same amount.​
bulgar [2K]

Answer:

2 books

Step-by-step explanation:

10 + 5x = 16 + 2x

    - 2x         - 2x

10 + 3x = 16

-10          -10

3x = 6

/3    /3

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What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that t
Inga [223]

Answer:

f(2n)-f(n)=log2

b.lg(lg2+lgn)-lglgn

c. f(2n)/f(n)=2

d.2nlg2+nlgn

e.f(2n)/(n)=4

f.f(2n)/f(n)=8

g. f(2n)/f(n)=2

Step-by-step explanation:

What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that the number of milliseconds the algorithm uses to solve the problem with input size n is each of these function? [Express your answer in the simplest form pos- sible, either as a ratio or a difference. Your answer may be a function of n or a constant.]

from a

f(n)=logn

f(2n)=lg(2n)

f(2n)-f(n)=log2n-logn

lo(2*n)=lg2+lgn-lgn

f(2n)-f(n)=lg2+lgn-lgn

f(2n)-f(n)=log2

2.f(n)=lglgn

F(2n)=lglg2n

f(2n)-f(n)=lglg2n-lglgn

lg2n=lg2+lgn

lg(lg2+lgn)-lglgn

3.f(n)=100n

f(2n)=100(2n)

f(2n)/f(n)=200n/100n

f(2n)/f(n)=2

the time will double

4.f(n)=nlgn

f(2n)=2nlg2n

f(2n)-f(n)=2nlg2n-nlgn

f(2n)-f(n)=2n(lg2+lgn)-nlgn

2nLg2+2nlgn-nlgn

2nlg2+nlgn

5.we shall look for the ratio

f(n)=n^2

f(2n)=2n^2

f(2n)/(n)=2n^2/n^2

f(2n)/(n)=4n^2/n^2

f(2n)/(n)=4

the time will be times 4 the initial tiote tat ratio are used because it will be easier to calculate and compare

6.n^3

f(n)=n^3

f(2n)=(2n)^3

f(2n)/f(n)=(2n)^3/n^3

f(2n)/f(n)=8

the ratio will be times 8 the initial

7.2n

f(n)=2n

f(2n)=2(2n)

f(2n)/f(n)=2(2n)/2n

f(2n)/f(n)=2

5 0
3 years ago
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