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Katena32 [7]
3 years ago
10

A 500-kg elevator is raised to a height of 20 m in 10 seconds. Calculate the power of the motor.

Physics
2 answers:
LuckyWell [14K]3 years ago
4 0

<>"power = 500 kg x 9.8 m/s² x 20 m / 10s = 9800 watts."<>

lyudmila [28]3 years ago
3 0

Answer:

Power, P =9800 W

Explanation:

It is given that,

Mass of the elevator, m = 500kg

It is raised to a height of 20 m in 10 seconds

Power is defined as the work done per unit time.

P=\dfrac{W}{t}

Work done is given by :

W=mgh

h is the height

So, P=\dfrac{mgh}{t}

P=\dfrac{500\ kg\times 9.8\ m/s^2\times 20\ m}{10\ s}

P = 9800 Watts

Hence, the power of the motor is 9800 W. The correct option is (b).

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1.71 km

Explanation:

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220V is applied to two different conductors made of the same material. One conductor is twice as long and twice as thick as the
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For first wire length is l₁ , area is A₁ resistance is R₁, for second resistance is R₂ , length is l₂ and area is A₂

Given , l₁ = 2l₂ , A₁ = 4A₂ , area is proportional to square of thickness.

R₁ / R₂ = I₁A₂ / I₂A₁

= 2l₂ x A₁ / 4 I₂A₁

= 1 / 2

2R₁ = R₂

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Ratio of power = (V² / R₁) x (R₂ / V²)

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7 0
3 years ago
susan and joe push a table 18 meters down a hall by exerting a force of 200 newtons (n). what is the total amount of work done o
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3600joules

Explanation:

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F=force (N)

S=displacement moved in the direction of force (m)

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2 years ago
A farsighted boy has a near point at 2.3 m and requires eyeglasses to correct his vision. Corrective lenses are available in inc
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Answer:

P = 3.5 D

Explanation:

As we know that convex lens is to be used to make the near point of eye to be correct

So we will have

\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}

here we have

d_i = 2.3 m = 230 cm

d_o = 25 cm

now plug in all values into the formula

-\frac{1}{230} + \frac{1}{25} = \frac{1}{f}

f = 28 cm

now for power of lens

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