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Katena32 [7]
3 years ago
10

A 500-kg elevator is raised to a height of 20 m in 10 seconds. Calculate the power of the motor.

Physics
2 answers:
LuckyWell [14K]3 years ago
4 0

<>"power = 500 kg x 9.8 m/s² x 20 m / 10s = 9800 watts."<>

lyudmila [28]3 years ago
3 0

Answer:

Power, P =9800 W

Explanation:

It is given that,

Mass of the elevator, m = 500kg

It is raised to a height of 20 m in 10 seconds

Power is defined as the work done per unit time.

P=\dfrac{W}{t}

Work done is given by :

W=mgh

h is the height

So, P=\dfrac{mgh}{t}

P=\dfrac{500\ kg\times 9.8\ m/s^2\times 20\ m}{10\ s}

P = 9800 Watts

Hence, the power of the motor is 9800 W. The correct option is (b).

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