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Katena32 [7]
3 years ago
10

A 500-kg elevator is raised to a height of 20 m in 10 seconds. Calculate the power of the motor.

Physics
2 answers:
LuckyWell [14K]3 years ago
4 0

<>"power = 500 kg x 9.8 m/s² x 20 m / 10s = 9800 watts."<>

lyudmila [28]3 years ago
3 0

Answer:

Power, P =9800 W

Explanation:

It is given that,

Mass of the elevator, m = 500kg

It is raised to a height of 20 m in 10 seconds

Power is defined as the work done per unit time.

P=\dfrac{W}{t}

Work done is given by :

W=mgh

h is the height

So, P=\dfrac{mgh}{t}

P=\dfrac{500\ kg\times 9.8\ m/s^2\times 20\ m}{10\ s}

P = 9800 Watts

Hence, the power of the motor is 9800 W. The correct option is (b).

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KIM [24]

Answer:

A) 1.5 v

B) Top plate is at higher voltage than the bottom plate

Explanation:

Battery value set between 0.0 V and 1.5 V

a) The potential difference between the plates

Δ V = V1( potential at top plate) - V2( potential at lower plate )

potential at top plate = 1.5 V

potential at lower plate = 0.0 V

hence potential difference = 1.5 V

b ) The top plate is always connected to the positive terminal of the DC source ( which is at a higher potential )while the bottom plate is connected to the negative terminal of the DC source ( which is at a lower potential )

hence the Top plate is at higher voltage than the bottom plate

7 0
3 years ago
Review:
Tresset [83]

Answer:

1. 1. A quantity is completely described by magnitude alone. A quantity Is completely described by a magnitude with a direction.

[a]. scalar, vector

b. vector, scalar

2.2. Speed is a velocity is a quantity and quantity.

a. scalar, vector

[b]. vector, scalar

3 0
2 years ago
As a physics instructor hurries to the bus stop, her bus passes her, stops ahead, and begins loading passengers. She runs at 6.0
Alika [10]

velocity of the physics instructor with respect to bus

v = 6 m/s

acceleration of the bus is given as

a = 2 m/s^2

acceleration of instructor with respect to bus is given as

a = -2 m/s^2

now the maximum distance that instructor will move with respect to bus is given as

v_f^2 - v_i^2 = 2 a d

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-36 = - 4 d

d = 9 m

so the position of the instructor with respect to door is exceed by

\delta x = 9 - 6 = 3 m

so it will be moved maximum by 3 m distance

7 0
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