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rjkz [21]
4 years ago
8

Two pool balls, each moving at 2 m/s, roll toward each other and collide. Suppose after bouncing apart, each moves at 2 m/s. Thi

s collision violates conservation of
A) Momentum.
B) Energy.
C) Both momentum and energy.
D) None of the above choices.
Physics
1 answer:
stira [4]4 years ago
4 0

Answer:D

Explanation:according to the law of conservation of energy/momentum, when two bodies collides, their total momentum and energy before and after collision are equal. Given that the two bodies move with the same velocities after collision, means that the law has not been violated since momentum = mass x velocity (where mass is constant)

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1850 psi

Explanation:

4 0
3 years ago
A ball is thrown vertically upward with an initial velocity of 25 m/s. What is its velocity after 3 seconds in the air? (assume
klasskru [66]

Answer:

v = -5 m/s

Explanation:

It is given that,

The initial velocity of the ball, u = 25 m/s

We need to find its velocity after 2 seconds in the air.

Let v is the velocity of the ball after 2 seconds. Using equation of motion to find it.

v = u + at

Here, a = -g

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v = 25 - (10)(3)

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3 years ago
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6 0
3 years ago
what is the period of a sound wave whose wavelength is 20.0m? use values from the book and show all of your work
Lera25 [3.4K]
The wavelength of a sound wave is related to its frequency by the relationship:
f= \frac{v}{\lambda}
where
f is the frequency
v is the speed of the wave
\lambda is the wavelength

The wave in our problem has wavelength of \lambda=20.0 m and speed of v=343 m/s (this is the speed of sound in air), therefore its frequency is
f= \frac{343 m/s}{20.0 m}=17.15 Hz

And the period of the wave is equal to the reciprocal of its frequency:
T= \frac{1}{f}= \frac{1}{17.15 Hz}=0.058 s
5 0
4 years ago
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<span>Sound travels fastest through solids, slower through liquids and slowest through gases.

Answer: Cast Iron, D.
</span>
3 0
3 years ago
Read 2 more answers
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