The distance traveled by the sprinter in meters is determined as 1.88 m.
<h3>Acceleration of the sprinter</h3>
The acceleration of the sprinter is the rate of change of velocity of the sprinter with time.
The acceleration of the sprinter is calculated as follows;
Apply Newton's second law of motion as follows;
F = ma
a = F/m
where;
- F is the applied force by the sprinter
- m is mass of the sprinter
- a is acceleration of the sprinter
a = 693 N / 64 kg
a = 10.83 m/s²
<h3>Distance traveled by the sprinter</h3>
The distance traveled by the sprinter is calculated as follows;
s = ut + ¹/₂at²
where;
- u is initial velocity = 0
s = ¹/₂at²
where;
- t is time of motion
- a is acceleration
s = (0.5)(10.83)(0.59²)
s = 1.88 m
Thus, the distance traveled by the sprinter in meters is determined as 1.88 m.
Learn more about distance here: brainly.com/question/2854969
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The correct answer to your question and how to solve it is
The relation between wavelength (λ)and the frequency of electromagnetic oscillation (f) is described by the following expression: λ=c/f, where c–is the speed of light in vacuum = 3*10^8 m/s
Derive f from above: f = c/λ.How to Calculate: λ=890nm = 890*10^-9m = 8.9*10^-7m
f =3*10^8m/s Divided by 8.9*10^-7m = 0.34*10^15 s-1=3.4*10^14 s-1
So your Answer is: The frequency of radiation of wavelength 890 nm is 3.4*10^14s-1
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