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stellarik [79]
3 years ago
9

How do you determine if a triangle is isosceles, scalene, or equilateral?

Mathematics
2 answers:
storchak [24]3 years ago
7 0

Answer:

A triangle is scalene if all of its three sides are different.  If two of its sides are equal, a triangle is called isosceles. A triangle with all three equal sides is called equilateral.

leva [86]3 years ago
3 0

You can identify the types of triangles by measuring their sides and angles. An equilateral triangle has three equal sides, and three angles that all equal 60 degrees. An isosceles triangle Has two equal sides and one smaller side, with two angles that are larger than the third. A scalene triangle has three different sides and three different angles.

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Three students are arguing over who can run the fastest. Student A says that she can run 2/3 mile in six minutes. Student B says
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Examine the table of equivalent ratios and complete this statement. For 5 servings, the ratio of cups of water to cups of juice
shepuryov [24]

Answer:

Step-by-step explanation:     This is five-fold proportion

The first ratio gives solution namely

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a:b= c:d= e:f = g:h= i:j = k

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When we divide 24/2 =12 our coefficient k=12

In the second ratio we will multiply 3 with 12 and get 36.

In the third ratio we will multiplu 5.5 with 12 and get 66.

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Finally the ratio is 24:2=36:3=66:5.5=108:9=180:15

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3 years ago
Read 2 more answers
Decimal And fraction in meters of 8 centimeters
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Ok so
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You can conclude and agree that 8 cm is 8/100, correct?
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This gives you 0.08
So the fraction is 8/100, which then can be simplified to 4/50, then to 2/25
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To find the area of parallelogram RSTU, Juan starts by drawing a rectangle around it. Each vertex of parallelogram RSTU is on a
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Read 2 more answers
|1/2b-8|=|1/4b-1|<br> b=____ and ____
Deffense [45]

Answer:

  b = 12 and 28

Step-by-step explanation:

The absolute value equation |1/2b-8| = |1/4b-1| resolves to a piecewise linear function with three pieces. There are two solutions.

<h3>Domains</h3>

The absolute value function on the left has a turning point where its value is zero:

  1/2b -8 = 0

  b -16 = 0

  b = 16

The absolute value function on the right has a turning point where its value is zero:

  1/4b -1 = 0

  b -4 = 0

  b = 4

For b > 16, both absolute value functions are identity functions. In this domain, the equation is ...

  1/2b -8 = 1/4b -1

For 4 < b < 16, the function on the left negates its argument, so the equation in this domain is ...

  -(1/2b -8) = 1/4b -1

For b < 4, both functions negate their arguments, so the equation in this domain is ...

  -(1/2b -8) = -(1/4b -1)

For the purpose of finding the value of b, this is effectively identical to the equation for b > 16. (The value of b does not change if we multiply both sides of the equation by -1.)

<h3>Solutions</h3>

<u>Domain b < 4 ∪ 16 < b</u>

  1/2b -8 = 1/4b -1

  2b -32 = b -4 . . . . . . . . multiply by 4

  b = 28 . . . . . . . . . . . . add 32-b to both sides

This solution is in the domain of the equation, so is one of the solutions to the original equation.

<u>Domain 4 < b < 16</u>

  -(1/2b -8) = 1/4b -1 . . . . equation in this domain

  -2b +32 = b -4 . . . . . . multiply by 4

  36 = 3b . . . . . . . . . . . add 2b+4 to both sides

  12 = b . . . . . . . . . . . . divide by 3

This solution is in the domain of the equation, so is the other solution to the original equation.

<h3>Graph</h3>

For the purposes of the graph, we have define the function g(b) to be the difference of the two absolute value functions. The solutions are found where g(x) = 0, the x-intercepts. The graph shows those to be ...

  b = 12  and  b = 28

__

<em>Additional comment</em>

Defining g(b) = |1/2b-8| -|1/4b-1|, we can rewrite it as ...

  g(b)=\begin{cases}7-\dfrac{1}{4}b&\text{for }b < 4\\-\dfrac{3}{4}b+9&\text{for }4\le b < 16\\\dfrac{1}{4}b-7&\text{for }16\le b\end{cases}

Then the solutions are the values of b that make g(b) = 0.

4 0
2 years ago
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