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Fed [463]
3 years ago
6

How can you find average speed

Physics
1 answer:
BabaBlast [244]3 years ago
4 0

Average speed =

(total distance covered)

divided by

(total time spent covering the distance)

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A man 2 meters tall walks at the rate of 2 meters per second toward a streetlight that's 5 meters above the ground. At what rate
GaryK [48]

Answer:

It changes at a rate of 4/3 meter per second

Explanation:

In the given figure below we have

\Delta OBD\simeq \Delta ABC\\\\\therefore \frac{5}{X+Y}=\frac{2}{Y}\\\\

Solving for Y given  X=2m/s we get

\frac{5}{2+Y}=\frac{2}{Y}\\\\5Y=4+2Y\\\\Y=\frac{4}{3}m/s

8 0
2 years ago
The James Webb Space Telescope will be the largest telescope ever put into space and will replace the Hubble Space Telescope. It
Nikolay [14]

Answer:

B : It will avoid the distortion from the atmosphere and give scientists more accurate data

Explanation:

5 0
3 years ago
An atom in the ground state has a collision with an electron, then emits a photon with a wavelength of 1240 nm. What conclusion
anyanavicka [17]

Answer:

attached below is the free body diagram of the missing  illustration

Initial kinetic energy of the electron = 3 eV

Explanation:

The conclusion that can be drawn about the kinetic energy of the electron is

E_{e} = E_{3}  - E_{1}

E_{e} = initial kinetic energy of the electron

E_{1} = -4 eV

E_{3} = -1 eV

insert the values into the equation above

E_{e} = -1 -(-4)  eV

   = -1 + 4 = 3 eV

6 0
3 years ago
julie is cycling at a speed of 3.4 meters/second. if the combined mass if the bicycle and julies is 30 kilograms. what is the ki
puteri [66]
You can solve this using the equation k=mv^2. k is the kinetic energy, m is the mass, and is the velocity. k=30(3.4)^2, so the answer is 346.8 J. 
3 0
3 years ago
two horses are pulling a 325 kg wagon, initially at rest. The horses exert 250 N and 178 N forward forces, respectively. Ignorin
Dovator [93]

Answer:

AFter 3.5 s, the wagon is moving at:   4.62\,\,\frac{m}{s}

Explanation:

Let's start by finding first the net force on the wagon, and from there the wagon's acceleration (using Newton's 2nd Law):

Net force = 250 N + 178 N = 428 N

Therefore, the acceleration from Newton's 2nd Law is:

F=m\,*\,a\\a = \frac{F}{m} \\a= \frac{428}{325}\, \frac{m}{s^2} \\a\approx 1.32 \,\,\frac{m}{s^2}

So now we apply this acceleration to the kinematic expression for velocity in an object moving under constant acceleration:

v_f=v_i+a\,*\,t\\v_f=0+1.32\,*\,3.5\,\,\frac{m}{s} \\v_f=4.62\,\,\frac{m}{s}

7 0
3 years ago
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