Answer:
6.03 m
Explanation:
First of all, let's convert the angular velocity from revolutions per minute to radians per second:
The frictional force on the block ranges from zero to a maximum value of
In order for the block to remain stuck on the turntable, the frictional force must be equal to the centripetal force, so we can write:
where
m is the mass of the block
is the angular velocity
r is the distance of the block from the centre
is the coefficient of static friction
g = 9.8 m/s^2
Solving for r, we find:
Answer:
40 mm
Explanation:
=Proper Length of rod = 2.05 m
Speed of rod = 6.01×10⁷ m/s
Length contraction
Final Length will be 2.01 m
So length that is contracted is 2.05-2.01 = 0.04 m
The length is contracted by 40 mm.
Answer:
Explanation:
It is given that,
Mass of the car 1,
Initial speed of the car 1,
Mass of the car 2,
Initial speed of the car 2,
It is mentioned that train cars are coupled together by being bumped into one another. Let V is the final velocity of the train cars after the collision. It can be calculated using the conservation of linear momentum as :
So, the final speed of the coupled train cars is 0.129 m/s towards x axis. Hence, this is the required solution.
The gravitational field is the Force divided by the mass
Call g the gravitational fiel, F the force exerted by the earth and m the mass of the telescope.
g = F / m
g=9.1x10^4 N / 1.1 x 10^4 kg = 8.27 N/kg
Note that the unit N/kg is equivalent to m/s^2