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eduard
3 years ago
13

A heavy meterstick has a mass of 1 kg. When the meterstick is thrown like a spear past you, you measure its momentum to be 2mv.

What do you measure its length to be?
Physics
1 answer:
CaHeK987 [17]3 years ago
4 0

Answer:

Its length is measured to be 0.5 m

Explanation:

From theory of relativity (mass variation), we know that:

m = mo/√(1-v²/c²)

Where, m = relative mass

and, mo = rest mass

The momentum of stick while moving, will be:

P = mv

but, it is given in the form of rest mass as:

P = 2(mo)v

thus, by comparison;

2(mo)v = mv

using value of m from theory of relativity;

2(mo)v = (mo)v/√(1-v²/c²)

√(1-v²/c²) = 1/2     ______ eqn(1)

Now, for relativistic length (L), we have the formula from same theory of relativity;

L = (Lo)√(1-v²/c²)

The rest length (Lo) of meter stick is 1 m, and the remaining term on right side √(1-v²/c²), known as Lorentz Factor, can be given by eqn (1), as equal to 1/2.

Thus,

L = (1 m)(1/2)

<u>L = 0.5 m</u>

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Answer:

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Explanation:

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Volume of an block is 5 cm3. If the density of the block is 250 g/cm3, what is the mass of the block ?​
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Answer:

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Explanation:

Given that the formula for density is ρ = mass/volume. Then you have to substitute the values into the formula :

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Answer:

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Explanation:

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Hope this helps!!

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