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DanielleElmas [232]
3 years ago
6

_______ occurs when a body’s molecular wavelength sends vibrations to another body, resulting in the production of another sound

wave.
Correct Answer
a) Resonance

b) Focusing
c) Refraction

Incorrect Response
d) Interference
Physics
2 answers:
Vikki [24]3 years ago
8 0
The answer is Resonance. Think of the bass on a speaker and if you place a glass of water onto a table or flat surface, it will start to vibrate/ shake because of the musics beats bass.
son4ous [18]3 years ago
8 0
Resonance is the answer.
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A mass of 240 grams oscillates on a horizontal frictionless surface at a frequency of 2.5 Hz and with amplitude of 4.5 cm.
mr_godi [17]

Answer:

(a) The spring constant is 59.23 N/m

(b) The total energy involved in the motion is 0.06 J

Explanation:

Given;

mass, m = 240 g = 0.24 kg

frequency, f = 2.5 Hz

amplitude of the oscillation, A = 4.5 cm = 0.045 m

The  angular speed is calculated as;

ω = 2πf

ω = 2 x π x 2.5

ω = 15.71 rad/s

(a) The spring constant is calculated as;

\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\k = m\omega ^2\\\\where;\\\\k \ is \ the \ spring \ constant\\\\k = (0.24) \times (15.71)^2\\\\k = 59.23 \ N/m

(b) The total energy involved in the motion;

E = ¹/₂kA²

E = (0.5) x (59.23) x (0.045)²

E = 0.06 J

5 0
3 years ago
Two planets P1 and P2 orbit around a star S in circular orbits with speeds v1 = 40.2 km/s, and v2 = 56.0 km/s respectively. If t
Readme [11.4K]

Answer: 3.66(10)^{33}kg

Explanation:

We are told both planets describe a circular orbit around the star S. So, let's approach this problem begining with the angular velocity \omega of the planet P1 with a period T=750years=2.36(10)^{10}s:

\omega=\frac{2\pi}{T}=\frac{V_{1}}{R} (1)

Where:

V_{1}=40.2km/s=40200m/s is the velocity of planet P1

R is the radius of the orbit of planet P1

Finding R:

R=\frac{V_{1}}{2\pi}T (2)

R=\frac{40200m/s}{2\pi}2.36(10)^{10}s (3)

R=1.5132(10)^{14}m (4)

On the other hand, we know the gravitational force F between the star S with mass M and the planet P1 with mass m is:

F=G\frac{Mm}{R^{2}} (5)

Where G is the Gravitational Constant and its value is 6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}

In addition, the centripetal force F_{c} exerted on the planet is:

F_{c}=\frac{m{V_{1}}^{2}}{R^{2}} (6)

Assuming this system is in equilibrium:

F=F_{c} (7)

Substituting (5) and (6) in (7):

G\frac{Mm}{R^{2}}=\frac{m{V_{1}}^{2}}{R^{2}} (8)

Finding M:

M=\frac{V^{2}R}{G} (9)

M=\frac{(40200m/s)^{2}(1.5132(10)^{14}m)}{6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}} (10)

Finally:

M=3.66(10)^{33}kg (11) This is the mass of the star S

4 0
3 years ago
Mayan kings and many school sports teams are named for the puma, cougar, or mountain lion felis concolor, the best jumper among
denis23 [38]
To reach a vertical height of 13.8 ft against gravity, which has an acceleration of 32 ft/s^2, the required vertical speed can be calculated from the equation:
vi^2 - vf^2 = 2*g*h
Given that it has vf = 0 (it is not moving vertically at its maximum height), g = 32, and h = 13.8, we can solve for vi:
vi^2 = 29.72 ft/s
This is only its vertical speed, so this is equivalent to its original speed multiplied by the sine of the angle:
29.72 ft/s = (v_original)*(sin 42.2<span>°</span>)
v_original = 44.24 ft/s
Converting to m/s, this can be divided by 3.28 to get 13.49 m/s.
4 0
3 years ago
A baseball player throws a baseball straight up into the air, the ball leaving his hand at time t = 0.0 s. The ball reaches maxi
laiz [17]

The ball should take twice as long to return to its original position as it took to reach its maximum height, so it should return to its original position at t=2.8\,\rm s.

4 0
2 years ago
How many years would it take to reach the planet saturn travelling at 21 thousand miles per hour? enter your answer with 2 decim
Dmitry_Shevchenko [17]

It would take about 4.8 years to travel from earth to Saturn.

<h3>How long would it take?</h3>

We know that speed is expressed as the ratio of distance to time. In this case, we are trying to know ow many years would it take to reach the planet Saturn travelling at 21 thousand miles per hour.

Given that;

Speed = 21 thousand miles per hour

time taken = ???

Distance = 887 million miles

Speed = distance/time

speed * time = distance

time = distance/speed

time = 8.87 * 10^8 miles/2.1 * 10^4  miles per hour

time = 4.22 * 10^4 hours

If 8.766 * 10^3 hours make 1 year

4.22 * 10^4 hours  make 4.22 * 10^4 hours * 1 year/8.766 * 10^3

= 4.8 years

Learn more about Saturn:brainly.com/question/12181523

#SPJ1

8 0
1 year ago
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