When the system is experiencing a uniformly accelerated motion, there are a set of equations to work from. In this case, work is energy which consist solely of kinetic energy. That is, 1/2*m*v2. First, let's find the final velocity.
a = (vf - v0)/t
2.6 = (vf - 0)/4
vf = 10.4 m/s
Then W = 1/2*(2100 kg)*(10.4 m/s)2
W = 113568 J = 113.57 kJ
It is because the equator is closer to the sun and because the sun's rays hit the surface of the Earth at a higher angle at the equator. The poles are colder because they don't get direct sunlight. The sun is always low on the horizon.
Answer:
Frequency = f = 10.0394 (1/s)
Explanation:
The frequency of oscillation of the system is given by the action:
f= √(k/m)
f= system count
k = spring constant
m = mass connected to the spring
Therefore the frequency will be:
f= √(k/m) = √(383(N/m) / (3.8kg))= √( 100.7895 (kg×m/s²)/(kg ) =
= √( 100.7895 (1/s²) = 10.0394 (1/s)
Okay so yeah u have to minus then subtract then decide it it’s a method i was taught to do
