From the solubility curve, which salt shows the least change in solubility as the temperature increases?

Chemistry

1 answer:

kari74 [83]3 years ago

4 0

Answer:NaCl (Sodium Chloride )

Explanation:As it has Solubility 35.7

You might be interested in

Kaila runs competitively. She would like to calculate her average running speed each time she runs. Which data should Kaila reco

Sladkaya [172]

Answer:

Start and end times; distance run.

Step-by-step explanation:

Average speed = distance/time.

Kaila should record the distance run, the time she started, and the time she ended her run.

The difference between the start and end times gives the time for the run.

If she inserts her numbers into the formula, she will get her average running speed.

4 0

4 years ago

Combining Boyle's law and Charles' law forms one presure-temperature-volume relationship and holds the mass of the gas constant.

Oksanka [162]

(P1V1/T1)=(P2V2/T2)

I just took the test and this should be correct

4 0

3 years ago

This graph shows two curves pertaining to a hydrogen s orbital.

fgiga [73]

Answer 1) : According to the complete question attached in the answer,

The radial wave function which is denoted by $R_{nl}(r)$ shown with orange color crosses through zero point. Also, At the the radial nodes, which are spherical shells to some radial distance away from the nucleus there no electron are found.

Also, the radial probability distribution curve denoted as $R^{2}_{nl}(r)$ shown in blue color is observed to touch zero, and shows the place of radial node.

Therefore, the total number of nodes will include both the kinds which has radial and angular nodes which will be represented by <em>'n'</em>.

It is observed that for any atomic orbital, the total number of nodes will be n-1 .

Considering the s orbital of the hydrogen, which has zero angular momentum (l); (l=0), as it has zero angular nodes.

Hence, there will be only radial nodes, which is

(n−1 = total number of radial nodes in s orbitals)

According to the image, there are 4 radial nodes shown, so n = 5 (as n-1 = 4; therefore, n = 5)

This represents the 5s orbital.

Answer 2) The radial nodes are observed in I'm seeing radial nodes at

$1.9a_{0}$ , $6.4a_{0}$ , $13.9a_{0}$ and $27.0a_{0}$ .

where $a_{0}$ represents the hydorgen bohr atomic radius = 0.0529177 nm

Explanation : It is quite easy to observe the given graph and find out the approximate values of the radial nodes, it does not requires any equation to be solved. Equation can be used to find the radial nodes if it was supplied along with the question. Although by mere speculation one can find out the answer.