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3 years ago

SCIENCEEEE!!!! I NEED HELPPP

Chemistry

2 answers:

seraphim [82]3 years ago

4 0

Both are physical changes.

Hope this helps!! (:

valina [46]3 years ago

3 0

These are both physical changes can I get a brain list please

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Plzz someone help me ASAP!

irina1246 [14]

The greater the friction, or rubbing, between particles in any fluid, the higher the viscosity. A fluid with a high viscosity has a large amount of internal friction. As the temperature of a gas increases, friction increases, and so the viscosity of the gas increases. The warmer the gas, the slower it flows.

3 0

3 years ago

What is a triple bond?

Pani-rosa [81]

The answer is A- single bonds made by 1 atom to 3 other atoms within a molecule

6 0

3 years ago

For the reaction 2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g). E∘=0.483 V what is the cell potential at 25 ∘C if the concentrations are [

Nesterboy [21]

Answer:

Ecel =0,04 V

Explanation:

Apply the Nerst equation,

Ecel= Ecelº - (RT/nF)*lnQ

where R=8,314 J/molK, T=25ºC=298K and F =96 485 Coulombs/mol e- and n=number of moles of electrons transferred in the balanced equation. Q is cocient of products and reactives power to respective coefficients, if is a gas apply partial pressure

Write the semiequation redox and verify the numbers of electron for balance. In this case you don't need to change nothing

2Cl−(aq)→Cl2(g) + 2e-

2CO3+(aq) + 2e-→2CO2+(aq)

2Cl−(aq) + 2CO3+(aq) →2CO2+(aq) + Cl2(g)

Hence

Ecel= 0.483 V - 0.013Ln ([CO2+]^2*PCl2] / [CO3+]^2*[Cl-]^2)

Ecel= 0.483 V - 0.013Ln ([0.205]^2 * 7.3] / [0.19]^2*[0.144]^2)

Ecel =0,04 V

6 0

3 years ago

Explain the difference between a neutron and a nucleus

marissa [1.9K]

The nucleus is the positively charged core of an atom, which is surrounded by a cloud of negatively charged electrons. Nucleons are particles that the core of an atom consists of, namely positively charged protons and neutral neutrons. That is, thenucleus is made up of nucleons.

6 0

3 years ago

When the following oxidation-reduction occurs, what is the balanced reduction half-reaction after the electrons in both half rea

Lostsunrise [7]

Answer : The balanced reduction half-reaction is:

$3Cu^{2+}+6e^-\rightarrow 3Cu$

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

The given balanced redox reaction is :

$Al(s)+Cu^{2+}(aq)\rightarrow Al^{3+}(aq)+Cu(s)$

The half oxidation-reduction reactions are:

Oxidation reaction : $Al\rightarrow Al^{3+}+3e^-$

Reduction reaction : $Cu^{2+}+2e^-\rightarrow Cu$

In order to balance the electrons, we multiply the oxidation reaction by 2 and reduction reaction by 3 and then added both equation, we get the balanced redox reaction.

Oxidation reaction : $2Al\rightarrow 2Al^{3+}+6e^-$

Reduction reaction : $3Cu^{2+}+6e^-\rightarrow 3Cu$

The balanced redox reaction will be:

$2Al(s)+3Cu^{2+}(aq)\rightarrow 2Al^{3+}(aq)+3Cu(s)$

Thus, the balanced reduction half-reaction is:

$3Cu^{2+}+6e^-\rightarrow 3Cu$

6 0

3 years ago