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otez555 [7]
3 years ago
6

The exact value for the density of aluminum is 2.699 g.cm^3. Working in the science lab at school, Joseph finds the density of a

piece of aluminum to be 2.75 g/cm^3. What is Joseph's percent error? (Round to the nearest hundredth.)
Chemistry
1 answer:
Alex787 [66]3 years ago
4 0

Joseph's percentage error would be 1.89%

<u>Explanation:</u>

Exact value of the density of aluminium = 2.699 g/cm³

Calculated value of the density of aluminium = 2.75 g/cm³

Percentage error = ?

We know:

Percentage error = \frac{experimental - exact}{exact} X 100\\\\

= \frac{2.75 - 2.699}{2.699} X 100\\\\= \frac{0.051}{2.699} X 100\\\\= 1.89\\

Therefore, Joseph's percentage error would be 1.89%

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part 2 : the initial concentration : 4.06 M

<h3>Further explanation </h3>

Dilution is the process of adding a solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution  

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\tt V_2=\dfrac{M_1.V_1}{M_2}\\\\V_2=\dfrac{44.8\times 0.73}{23.3}\\\\V_2=1.404~L

part 2 :

V₁=739 ml=0.739 L

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