Question

The exact value for the density of aluminum is 2.699 g.cm^3. Working in the science lab at school, Joseph finds the density of a piece of aluminum to be 2.75 g/cm^3. What is Joseph's percent error? (Round to the nearest hundredth.)

Answer 1

Joseph's percentage error would be 1.89%

Explanation:

Exact value of the density of aluminium = 2.699 g/cm³

Calculated value of the density of aluminium = 2.75 g/cm³

Percentage error = ?

We know:

$Percentage error = \frac{experimental - exact}{exact} X 100$

$= \frac{2.75 - 2.699}{2.699} X 100\\\\= \frac{0.051}{2.699} X 100\\\\= 1.89$

Therefore, Joseph's percentage error would be 1.89%