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lorasvet [3.4K]
2 years ago
14

If atoms are made of smaller parts suchas electrons, why are atoms considered thebasic unit of matter?

Chemistry
2 answers:
drek231 [11]2 years ago
6 0

Answer:

Explanation:

The reason for that is because atoms make elements needed for survival(oxygen, hydrogen, nitrogen, carbon, etc.).

Anika [276]2 years ago
6 0

Answer:

As atoms make up elements

Hope this helped :)

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What would be the number of oxygen atoms in 5.00 moles of co2?
malfutka [58]
Well theres 5 so times 2 equals 10

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3 years ago
Which statements correctly describe atmospheric pressure?
Shalnov [3]

Answers are:

2. It pushes on all objects that are on Earth’s surface.

3. It can be measured in atmospheres or kilopascals.

Barometric pressure (atmospheric pressure), is the pressure within the atmosphere of Earth

Atmospheric pressure decreases with increasing height, because there are fewer air molecules above a given object.

Barometer is an instrument used in meteorology to measure atmospheric pressure.

Atmospheric pressure (atm) is the force per unit area by the weight of air above that point.  

Kilopascal (kPa) is a metric system pressure unit and equals to 1000 force of newton per square meter.

Atmospheric pressure results from molecular collisions of atmospheric gases.

4 0
3 years ago
Trans fats: Think about how the prefix trans- is used in naming alkenes.
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In an alkene, cis and trans isomers are possible because the double band is rigid, cannot rotate, has groups attached to the carbons of the double bond that are fixed relative to each other, and only occurs with double bonds-possibility that molecule will have different geometries; two different molecules with slightly different properties. 
-Trans-2 ends of chain across the double bond.
While naming Cis-Trans isomers the prefix cis or trans are placed in front of the alkene name when there are cis-trans isomers. 
4 0
2 years ago
Read 2 more answers
Consider the following mechanism for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution. H+ + H2O2 ? H3
Margarita [4]

<u>Answer:</u> The rate law for the reaction is \text{Rate}=k'[H+][H_2O_2][Br^-]

<u>Explanation:</u>

Rate law is the expression which is used to express the rate of the reaction in terms of the molar concentration of reactants where each term is raised to the power their stoichiometric coefficient respectively from a balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

The chemical equation for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution follows:

2H^++2Br^-+H_2O_2\rightarrow Br_2+2H_2O

The intermediate reaction of the mechanism follows:

<u>Step 1:</u>  H^++H_2O_2\rightleftharpoons H_3O_2^+;\text{ (fast)}

<u>Step 2:</u>  H_3O_2^++Br^-\rightarrow HOBr+H_2O;\text{(slow)}

<u>Step 3:</u>  HOBr+H^++Br^-\rightarrow Br_2+H_2O;\text{(fast)}

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

\text{Rate}=k[H_3O_2^+][Br^-]          ......(1)

As, [H_3O_2^+] is not appearing as a reactant in the overall reaction. So, we apply steady state approximation in it.

Applying steady state approximation for [H_3O_2^+] from step 1, we get:

K=\frac{[H_3O_2^+]}{[H^+][H_2O_2]}  

[H_3O_2^+]=K[H^+][H_2O_2]

Putting the value of [H_3O_2^+] in equation 1, we get:

\text{Rate}=k.K[H^+][H_2O_2][Br^-]\\\\\text{Rate}=k'[H+][H_2O_2][Br^-]

Hence, the rate law for the reaction is \text{Rate}=k'[H+][H_2O_2][Br^-]

4 0
3 years ago
For the hypothetical reaction: A + B ---&gt; 2C, write an expression that relates the disappearance of A and B to the appearance
forsale [732]

Answer:

Rate expression has been given below

Explanation:

According to the given equation, 1 molecule of A reacts with 1 molecule of B and produces 2 molecules of B at a time.

So, rate of disappearance of both A and B are one half of rate of appearance of B

Hence rate expression can be represented as:

Rate=\frac{-\Delta [A]}{\Delta t}=\frac{-\Delta [B]}{\Delta t}=\frac{1}{2}\frac{\Delta [C]}{\Delta t}

where \frac{-\Delta [A]}{\Delta t} is rate of disappearance of A, \frac{-\Delta [B]}{\Delta t} is rate of disappearance of B and \frac{\Delta [C]}{\Delta t} rate of appearance of C

8 0
3 years ago
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