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Sladkaya [172]
3 years ago
11

Which end is hydrophilic

Biology
1 answer:
Marina CMI [18]3 years ago
5 0

Answer:

let me know if that helped

Explana

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Oompah’s with type O blood receive a tax break. ophine oompah has type a blood, but he wants a wife that will give him children
vova2212 [387]

Answer:

He should request type O on his dating survey.

Opine's blood type must be AO to have a higher probability of producing O offsprings.

Explanation:

O blood type is recessive so, when it is paired with another blood type like B or A, these would be dominant, giving B and A blood, respectively.

O blood type results are possible thanks to OO genotypes.

If the man's blood type is A, to have a higher chance of producing OO offsprings, his blood should be AO. The other possibility is that he has AA blood, which will result in a low probability of OO offsprings.

As regards the mother, her blood type should be OO.

We can see this more clearly in Punnet Square.

<u> ║ A ║O</u>

<u>O║AO║OO</u>

<u>O║AO║OO</u>  

There is a 50% of probability of having O offsprings with AO and OO.

  <u>║ A ║A</u>

<u>O║AO║AO</u>

<u>O║AO║AO </u>

With AA and OO, the probability is 0%

 <u>║ A ║O</u>

<u>A║AA║AO</u>

<u>O║AO║OO</u>

With both parents having AO, blood the probability of having a OO offspring is 25%.

In conclusion, the higher chances of producing a OO offspring is if the parents are AO and OO.

3 0
2 years ago
Nitrogen-fixing bacteria convert atmospheric nitrogen into forms of nitrogen that living things can use.
RoseWind [281]
I’m pretty sure it’s true
3 0
3 years ago
Glucose-6-phosphate dehydrogenase deficiency (G6PD) is inherited as an X-linked recessive allele in humans. A woman whose father
prohojiy [21]

Answer:

(a) 1/2; (b) no

Explanation:

Glucose-6-phosphate dehydrogenase deficiency (G6PD) is an X-linked recessive disorder and the woman's father was diseased so it means that woman is a carrier of the allele but has normal phenotype. It means that she will have XXᵇ genotype.

In contrast to this, her husband is diseased so his genotype will be XᵇY.

The Punnett square diagram related to the cross is attached.

(a) Proportion of their sons expected to be G6PD is 1/2:

They both may give birth to 4 progeny with genotypes XXᵇ, XᵇXᵇ, XY and XᵇY. It means they both may have 2 sons out of which one with genotype XᵇY will be diseased while the one with genotype XY will be healthy. So the proportion of their sons having G6PD is 1/2 or 50%.

(b) If the husband were G6PD deficient, the answer will not change.

The reason behind this is that this disease is caused by an allele located in X chromosome. But father contributes only Y chromosome to his son not X chromosome. The X chromosome will affect the genotype of his daughter not son that is why answer will not change. It means they will still have 1/2 of their sons diseased.  

7 0
3 years ago
A fellow veterinary technician student tells you that animals undergoing examination should be restrained with maximum force to
weeeeeb [17]

Answer: Animals undergoing examination should be restrained with just enough force to calm them and keep them still so that the veterinarian can provide proper veterinary care. Each animal's restraint needs will be different and dependent on their behaviors and anatomies.

7 0
3 years ago
Name the planets in order from the sun.
Karolina [17]

Answer: Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune

Explanation:

7 0
3 years ago
Read 2 more answers
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