Answer:
0.09375M
Explanation:
There are two methods of going about this, either we use dilution formula (easiest and fastest) or we solve through molarity.
Using dilution formula,
C2 (H2SO4) = ?
C1 (NaOH) = 0.25M
V2 (H2SO4) = 20cm³
V1 (NaOH) = 15cm³
However we can solve using molarity method
Equation of reaction =
2NaOH + H2SO4 ====》 Na2SO4 + 2H2O
O.25M of NaOH = 1000cm³
X moles = 15cm³
X = (0.25 * 15) / 1000
X = 0.00375 moles is present in 15cm³ of NaOH
From equation of reaction,
2 moles of NaOH requires 1 mole of H2SO4
Therefore
0.00375 / 2 = 0.001875 moles is present in H2SO4
From the reaction,
0.00187 moles of H2SO4 = 20 cm³
X moles = 1000cm³
X = (0.00187*1000) / 20 = 0.09375M
Answer:
2. precipitate is formed
Explanation:
In this reaction barium nitrate and sodium sulfate solutions react to form a barium sulfate precipitate.Barium and sulfate ions will react to give barium sulfate precipitate where as the sodium and nitrate ions are spectator ions.
The net ionic equation after removing unchanged ions from each side of the full ionic equation will be;
Ba²⁺+ SO₄²⁻ → BaSO₄ (s)
Answer:
The full amount (5.00 g) will be dissolved in 1 L of water at 25°C.
Explanation:
The molecular weight (MW) of Vanillin (C₈H₈O₃) is calculated from the chemical formula as follows:
MW(C₈H₈O₃) = (12 g/mol x 8) + (1 g/mol x 8) + (16 g/mol x 3) = 152 g/mol
If 0.070 mol of C₈H₈O₃ are soluble per liter of water at 25°C, the maximum mass that can be dissolved in 1 L is:
0.070 mol x 152 g/mol = 10.64 g
Since 5.00 g is lesser than the maximum amount that can be dissolved (10.64 g), the added amount will be completely dissolved in 1 L of water at 25°C.
