Answer:
Explanation:
Using the expression,
Where,
is the activation energy
R is Gas constant having value = 8.314 J / K mol
So,
There is 18 + 633= 651 grams of HCl in aqueous form depending how the reaction is done
1. First calculate the total molar mass of the entire compound.
Mg = 3 x 24.31 = 72.93 g/mol
P = 2 x 30.97 = 61.94 g/mol
O = 8 x 16.00 = 128.00 g/mol
* Add them up;
72.93 + 61.94 + 128.00 = 262.87 g/mol
2. Take the individual masses of each element that you calculated, divide them by the total mass (262.87 g/mol) and then multiply by 100.
Mg = 72.93/262.87 = 0.2774 x 100 = 27.74%
P = 61.94/262.87 = 0.2356 x 100 = 23.56%
O = 128.00/262.87 = .4870 x 100 = 48.70%
3. All of the percentages should add up to equal 100%.
* Hope this helps
<em>Refer to the attachment </em><em>!</em><em>!</em><em>!</em>
Answer:
86.2 g/mol
Explanation:
Before you can find the molar mass, you first need to calculate the number of moles of the gas. To find this value, you need to use the Ideal Gas Law:
PV = nRT
In this equation,
-----> P = pressure (mmHg)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas constant (62.36 L*mmHg/mol*K)
-----> T = temperature (K)
After you convert the volume from mL to L and the temperature from Celsius to Kelvin, you can use the equation to find the moles.
P = 760 mmHg R = 62.36 L*mmHg/mol*K
V = 250 mL / 1,000 = 0.250 L T = 20 °C + 273.15 = 293.15 K
n = ? moles
PV = nRT
(760 mmHg)(0.250 L) = n(62.36 L*mmHg/mol*K)(293.15 K)
190 = n(18280.834)
0.0104 = n
The molar mass represents the mass (g) of the gas per every 1 mole. Since you have been given a mass and mole value, you can set up a proportion to determine the molar mass.
<----- Proportion
<----- Cross-multiply
<----- Divide both sides by 0.0104