Determine the concentration of a solution prepared by diluting 20.0 mL of 2.00 M NaCl to 250.0 mL. Please show your work.
1 answer:
0.16 M is the concentration of a solution prepared by diluting 20.0 ml of 2.00 M NaCl to 250.0 ml.
Explanation:
Data given:
Initial volume of NaCl, V1 = 20 ml
initial molarity of the NaCl solution = 2M
Final volume of the NaCl solution = 250 ml
final molarity of the diluted solution = ?
from the information given, the formula for dilution used is:
Minitial Vinitial = Mfinal Vfinal
putting the values in the rearranged equation:
V final =
V final =
Mfinal = 0.16 M
Thus it can be seen that when a 20 ml solution having molarity of 2M is diluted to 250 ml the molarity decreases to 0.16 M.
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Explanation:
Ionic bonds are formed when atoms transfer electrons. (In contrast, covalent bonds are formed when atoms share electrons.)
There's a distinction between the two: when two atoms react to form an ionic bond, one atom would completely lose one electron, while the other would completely gain that electron. The atom that loses the electron becomes a positively-charged ion called a cation, whereas the atom that gains the electron becomes a negatively-charged ion called an anion.
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Answer: 0.151
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
Given:
Putting in the values we get:
Thus the rate of appearance of is 0.151