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Evgesh-ka [11]
3 years ago
5

In this lab, you will use a dynamics track to generate collisions between two carts. If momentum is conserved, what variable cha

nge would result in a velocity change after a collision? In the space below, write a scientific question that you will answer by doing this experiment.
answer for E2020: How does changing mass affect colliding objects?
Physics
2 answers:
tangare [24]3 years ago
8 0

Here by momentum conservation we can write

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

so here from above equation we can say the final speed after collision depends upon the mass of two objects

here if we change the mass of two colliding object then the final speed will change

for example

If we take two objects of same masses then after collision the speed of two objects will interchange

While if the two colliding object are such that one of the object is very heavy then after collision there is no effect on its velocity.

So if mass is changed then the speed of the object after collision will change

the speed of object after collision is given by

v_{1f} = \frac{m_1 - m_2}{m_1+m_2}v_{1i} + \frac{2m_2}{m_1+m_2}v_{2i}

v_{2f} = \frac{m_2 - m_1}{m_1+m_2}v_{2i} + \frac{2m_1}{m_1+m_2}v_{1i}

So by above equations we can show the dependency of two speed on mass

Paha777 [63]3 years ago
8 0

How does changing mass affect colliding objects?

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A person who weighs 509,45 N empties her lungs as much as
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Answer:

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Explanation:

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From Archimedes principle,

R.d = Density of the person/Density of water = Weight of the person in air/Upthrust.

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Where D₁ = Density of the person, D₂ = Density of water, W = Weight of the person in air, U = Upthrust in water.

Making D₁ the subject of the equation,

D₁ = D₂(W/U)................................... Equation 2

<em>Given: D₂ = 1000 kg/m³ , W = 509.45 N, U = lost in weight = weight in air - weight in water = 509.45 - 22.34 = 487.11 N</em>

<em>Substituting these values into equation 2</em>

D₁ = 1000(509.45/487.11)

D₁ = 1045.86 kg/m³

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7 0
4 years ago
A man is sitting on a chair with wheels. He grabs a 2.1 kg book from the desk and throws
geniusboy [140]

The speed of the man and the chair after the book is thrown is 0.2 m/s.

The given parameters:

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m₂ = 70 kg + 9.2 kg

m₂ = 79.2 kg

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Thus, the speed of the man and the chair after the book is thrown is 0.2 m/s.

Learn more about conservation of linear momentum here: brainly.com/question/7538238

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