_NaNO3+__ Pbo-> __pb(NO3)2+__na2o
1 answer:
2NaNO₃ + PbO → Pb(NO₃)₂ + Na₂O
Explanation:
Given expression:
NaNO₃ + PbO → Pb(NO₃)₂ + Na₂O
We can use a simple mathematical approach to balance this equation by setting up small algebraic equations.
aNaNO₃ + bPbO → cPb(NO₃)₂ + dNa₂O
a,b,c and d are the coefficients that will balance the equation
Conservation of Na: a = 2d
N: a = 2c
O: 3a + b = 6c + d
Pb: b = c
let a = 1
b =
c =
d =
multiply all through by 2:
a = 2 , b = 1 , c = 1 and d = 1
2NaNO₃ + PbO → Pb(NO₃)₂ + Na₂O
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balanced equation brainly.com/question/2612756
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Answer: A mass of 124457.96 g ammonia is produced by reacting a 450 L sample of nitrogen gas at a temperature of 450 K and a pressure of 300 atm.
Explanation:
Given: Volume = 450 L
Temperature = 450 K
Pressure = 300 atm
Using ideal gas equation, moles of nitrogen are calculated as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = tempertaure
Substitute values into the above formula as follows.
According to the given equation, 1 mole of nitrogen forms 2 moles of ammonia. So, moles of ammonia formed by 3654.08 moles of nitrogen is as follows.
As moles is the mass of substance divided by its molar mass. So, mass of ammonia (molar mass = 17.03 g/mol) is as follows.
Thus, we can conclude that a mass of 124457.96 g ammonia is produced by reacting a 450 L sample of nitrogen gas at a temperature of 450 K and a pressure of 300 atm.