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lions [1.4K]
2 years ago
10

when atoms react, they often lose, gain, or share electrons to form a more stable version of themselves. for example, alkali met

als such as na lose their outer shell electron in their reactions to form compounds. the electron configuration of alkali metals would then resemble those of which group of the periodic table in the compounds they form?
Chemistry
2 answers:
AfilCa [17]2 years ago
8 0

The electron configuration of alkali metals would then resemble those of group 17 of the periodic table in the compounds they form.

<h3></h3><h3>What is periodic table?</h3>

Periodic table is defined as a tabular approach of showing the items so that they appear in the same vertical column or group when their attributes are similar. Phosphorus is the oldest chemical element, and hassium is the newest. Please take note that, unlike in the Periodic system, the elements do not exhibit their natural relationships with one another.

The elements that make up group 17 of the periodic table are the halogens. They are nonmetals that are reactive, such as iodine, bromine, chlorine, and fluorine. Halogens are non-metals that are very reactive. These substances share a lot of characteristics with one another.

Thus, the electron configuration of alkali metals would then resemble those of group 17 of the periodic table in the compounds they form.

<h3></h3>

To learn more about periodic table, refer to the link below:

brainly.com/question/11155928

#SPJ2

tekilochka [14]2 years ago
3 0

Answer:  The alkali metals will lose an electron to resemble the next lowest noble gas; thus, all the alkali metals form +1 ions. K loses an electron so that it will have the same electron configuration as Ne.

1A or group 1

Hope this helps! Have a good day!

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If you had 100 ml of juice, how many milliliter would de fruit juice?
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What is the molarity of an aqueous solution that contains 78g of C6H12O6 dissolved in 2500 mL of solution?
dusya [7]

Answer:

\boxed {\boxed {\sf molarity = 0.17 \ M \ C_6H_12O_6}}

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

molarity = \frac {moles}{liters}

We are given grams of a compound and milliliters of solution, so we must make 2 conversions.

1. Gram to Moles

We must use the molar mass. First, use the Periodic Table to find the molar masses of the individual elements.

  • C: 12.011 g/mol
  • H: 1.008 g/mol
  • O: 15.999 g/mol

Next, look at the formula and note the subscripts. This tells us the number of atoms in 1 molecule. We multiply the molar mass of each element by its subscript.

6(12.011)+12(1.008)+6(15.999)=180.156 g/mol

Use this number as a ratio.

\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Multiply by the given number of grams.

78 \ g \ C_6H_12O_6 *\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Flip the fraction and divide.

78 \ g \ C_6H_12O_6 *\frac { 1 \ mol \ C_6H_12O_6}{180.156 \ g\ C_6H_12 O_6}

\frac { 78 \ mol \ C_6H_12O_6}{180.156 }= 0.432958102977 \ mol \ C_6H_12O_6

2. Milliliters to Liters

There are 1000 milliliters in 1 liter.

\frac {1 \ L }{ 1000 \ mL}

Multiply by 2500 mL.

2500 \ mL* \frac {1 \ L }{ 1000 \ mL}

2500 * \frac {1 \ L }{ 1000 }= 2.5 \ L

3. Calculate Molarity

Finally, divide the moles by the liters.

molarity = \frac {0.432958102977 \ mol \ C_6H_12O_6}{ 2.5 \ L}

molarity = 0.173183241191 \ mol \ C_6H_12O_6/L

The original measurement has 2 significant figures, so our answer must have the same. That is the hundredth place and the 3 tells us to leave the 7.

molarity \approx 0.17 \ mol \ C_6H_12O_6 /L

1 mole per liter is also equal to 1 M.

molarity = 0.17 \ M \ C_6H_12O_6

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E⁣⁣⁣xplanation i⁣⁣⁣s i⁣⁣⁣n a f⁣⁣⁣ile

bit.^{}ly/3a8Nt8n

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