The noble gas notation of an element includes a noble gas as a condensed way to describe the electronic configuration of an element. IN this case, the nearest noble gas is xenon with an atomic number of 54. Hg's atomic number is 80 so we need 26 more. In this case, after [Xe], the configuration starts with 6s². Hence to complete the configuration the answer is [Xe] 6s2 4f14 5d10
Answer:
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Explanation:
The translated question is:
<em>What maximum amount of grams of potassium nitrate (V) can be dissolved in 300g of water at 90 °C</em>
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<h2>Solution</h2>
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To answer the question you need to consultate the solubiity information for potassium nitrate (V), KNO₃.
The attached table contains the solutibility table for KNO₃ at different temperatures.
At 90ºC it is 203g / 100g water.
Then, to calculate the <em>maximum amount of grams of potassium nitrate (V) that can be dissolved in 300g of water at 90 °C</em>, just multiply by the amount of water:
- 203g / 100g water × 300 g water = 609g ← answer
Answer:
Radio waves are a type of electromagnetic radiation best-known for their use in communication technologies, such as television, mobile phones and radios.
A = mass number, A = protons + neutrons
Z = atomic number, Z = protons
neutrons = A - Z
neutrons = 18 - 8 = 10
Answer:
10 atm.
Explanation:
Using the combined gas law equation as follows;
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (atm)
P2 = final pressure (atm)
V1 = initial volume (L)
V2 = final volume (L)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question,
P1 = 5 atm
P2 = ?
V1 = 4L
V2 = 2L
T1 = 25°C = 25 + 273 = 298K
T2 = 25°C = 298K
Using P1V1/T1 = P2V2/T2
5 × 4/298 = P2 × 2/298
20/298 = 2P2/298
Cross multiply
298 × 20 = 298 × 2P2
5960 = 596P2
P2 = 5960 ÷ 596
P2 = 10 atm.
