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3 years ago

What is constant on wet asphalt?

Chemistry

1 answer:

wariber [46]3 years ago

6 0

Answer:

Friction and Automobile Tires. ... On dry surfaces you might get as high as 0.9 as a coefficient of friction, but driving them on wet roads would be dangerous since the wet road coefficient might be as low as 0.1

Explanation:

hope this helps

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Do plasmids have an importance beyond the practice of genetic engineering?

kozerog [31]

Answer: Yes

Explanation: Plasmids offer a number of unique characteristics that make genetic engineering much more efficient. Plasmids are a type of non-chromosomal DNA. Integrating DNA into a bacterial or other chromosome is far more complex than simply putting DNA into a cell; plasmids make it easier to transport DNA into a cell by eliminating this step.

4 0

2 years ago

Enter the symbol of a sodium ion, Na+, followed by the formula of a sulfate ion, SO42−. Separate the ions with a comma only—spac

gladu [14]

Na⁺,SO₄²⁻ is the answer

<h3>Further explanation </h3>

An ion is an atom or molecule that has a net electrical charge. There are many ions, one of them are sodium ion and sulfate ion.

SO₄²⁻ or Sulfate is a naturally occurring polyatomic ion that consist of a central sulfur atom surrounded by four oxygen atoms with occured widely in everyday life. Sodium ions are important for regulation of blood and body fluids, transmission of nerve impulses, heart activity, and certain metabolic functions.

Whereas Na⁺ or Sodium is a chemical element with the symbol Na and atomic number 11. It is a soft, silvery-white, highly reactive metal. Sulfate ion is a very weak base. Therefore sulfate ion undergoes negligible hydrolysis in aqueous solution.

Enter the symbol of a sodium ion, Na⁺, followed by the formula of a sulfate ion, SO₄²⁻. Separate the ions with a comma only—spaces are not allowed. Express your answers as ions separated by a comma. Therefore the answer is: Na⁺,SO₄²⁻

Hope it helps!

<h3>Learn more</h3>

Learn more about sodium ion brainly.com/question/6839866
Learn more about sulfate ion brainly.com/question/2763823
Learn more about ions brainly.com/question/11852357

<h3>Answer details</h3>

Grade: 9

Subject: Chemistry

Chapter: Introduction to Mastering Chemistry

Keywords: sodium ion, sulfate ion, ions, Chemistry, symbol

6 0

3 years ago

Read 2 more answers

Which of the following is a type of matter

Ira Lisetskai [31]

Everything on Earth can be easily described in terms of one of four forms of matter: solid, liquid, gas, and plasma. Students are familiar with the three common forms of matter: solids, liquids, and gases. A solid is an object that has a form.

plz mark me as brainliest if this helped :)

7 0

3 years ago

Read 2 more answers

A woman is experiencing false labor if the contractions...

Allisa [31]

Answer:

Before "true" labor begins, you might have "false" labor pains, also known as Braxton Hicks contractions.

Explanation:

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3 years ago

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A compound with molecular formula C5H10O2 has the following 1H NMR spectrum: 1.15 (t, 3H), 1.25 (t, 3H), 2.33 (q, 2H), 4.13 (q,

Vilka [71]

Answer:

Ethyl propionate

Explanation:

Calculating the double bond equivalence as:

DBE = C - (H/2) - (X/2) + (N/2) +1

Where

C is the number of carbon atoms

N is the number of nitrogen atoms

X is the number of halogens

H is the number of hydrogen atoms

So, according to the formula, $C_5H_{10}O_2$

DBE = 5 - (10/2) - (0/2) + (0/2) +1 = 1

It means there is one double bond or one ring.

from the NMR signal, it is clear that compound has two triplet and two quardrate group that means two -CH3 and two -CH2 groups are present.

From the splitting information, it is clear that each the -CH2- group is next to a -CH3, and vice-versa. In this case ring structure is not possible.

The chemical shift of two protons 4.13 ppm(q, 2H) is for protons next to an O atom, therefore, compound must have

$-OCH_2CH_3$ .

Then the signal at 2.33 is for a -CH2-group next to a C=O. So compound must have a structure CH3-CH2-C=O. Now, there is only one way to complete the structure - by bonding the O to the C=O carbon.

So the compound is ethyl propionate

3 0

3 years ago