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2 years ago

Competition for resources within an elk herd living in a national park can become severe. What

Chemistry

1 answer:

harkovskaia [24]2 years ago

6 0

High popularity density

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Question 4

vazorg [7]

Answer:

H(aq) + NO3 (aq) + HF(aq)

Explanation:

In the given mixture of HNO3 (Nitric Acid) and HF (hydrofluoric acid) in water the major species present are H(aq) + NO3 (aq) + HF(aq).

On the reaction of HNO3 (Nitric Acid) and HF (hydrofluoric acid) in water , it will give a polar solution and will form a homogenous mixture.

Hence, the correct answer is "H(aq) + NO3 (aq) + HF(aq)".

4 0

2 years ago

Help me please i need it for homework i cant seen to solve the answer :((

strojnjashka [21]

Bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb

7 0

2 years ago

If an object has an acceleration of 9.8 m/s and a force of 58.8N what is the mass of an object ? What could the object be

Makovka662 [10]

Answer:

The mass of an object is 0.6122 Kg

Explanation:

Given:

Acceleration = 9.8 m/s

Force = 58.8 N

To Find:

Mass of an object = ?

Solution:

We know that according to newtons 2nd law

Force is the product of the mass and acceleration

F= ma

where

F = Force

m = mass

a = Acceleration

Substituting the values,

58.8 = m X 9.8

$m= \frac{58.8}{9.8}$

m = 0.6122 kg

7 0

2 years ago

What is true of diffusion

Fed [463]

Molecules move from areas of high concentration to areas of low concentration.

7 0

2 years ago

Calculate hydrochloric acid (umol)in 200 ul of a 0.5173Msolution of acid?

strojnjashka [21]

Answer: The moles of hydrochloric acid is $1.0346\times 10^{-4}\mu mol$

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Or,

$\text{Molarity of the solution}=\frac{\text{Micro moles of solute}\times 10^6}{\text{Volume of solution (in }\mu L)}}$

We are given:

Molarity of solution = 0.5173 M

Volume of solution = $200\mu L$

Putting values in above equation, we get:

$0.5173M=\frac{\text{Micro moles of HCl}\times 10^6}{200\mu L}\\\\\text{Micro moles of HCl}=1.0346\times 10^{-4}\mu mol$

Hence, the moles of hydrochloric acid is $1.0346\times 10^{-4}\mu mol$

7 0

2 years ago