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3 years ago

Find the density of a material given that a 5.03g sample occupies 3.24ml

Chemistry

1 answer:

Verizon [17]3 years ago

3 0

Formula for density:

D = Mass / Volume

Mass = 5.03g

Volume = 3.24ml

Formula in our case:

D = 5.03 / 3.24

$D = 0.31~g/m^{3}$

Hope it helped,

BioTeacher101

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Each molecule of lycopene contains 40 atoms of carbon (plus other atoms). The mass percent of carbon in lycopene is 84.49%. What

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Answer: 568g/mol

Explanation:

It should be noted that there are 40 atoms of carbon in lycopene.

Since mass of 1 carbon = 12g/mol

Mass of 40 carbon atoms = 40 × 12g/mol = 480g/mol

Let the molar mass of lycopene be represented by x.

Therefore the molar mass of carbon = x × mass percent of carbon in lycopene

x × 84.49% = 480g/mol

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2 years ago

How much ice (in grams) would have to melt to lower the temperature of 353 mL of water from 26 ∘C to 6 ∘C? (Assume the density o

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Answer:

The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg

Explanation:

Heat gain by ice = Heat lost by water

Thus,

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Where, negative sign signifies heat loss

Or,

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For ice:

Mass = x g

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Final temperature = 6 °C

Specific heat of ice = 1.996 J/g°C

For water:

Volume = 353 mL

$Density (\rho)=\frac{Mass(m)}{Volume(V)}$

Density of water = 1.0 g/mL

So, mass of water = 353 g

Initial temperature = 26 °C

Final temperature = 6 °C

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So,

$334x+x\times 1.996\times (6-0)=353\times 4.186\times (26-6)$

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Thus,

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