Answer: 1-Phenyl ethyl radical is formed as an intermediate in the reaction and since Phenyl ethyl radical has a trigonal planar geometry so it is a planar molecule having two faces. So Br radical radical can recombine with the two faces with equal probability leading to a racemic mixture in 50:50ratio of products.Hence two products are formed which are known as enatiomers.
Explanation:
When we irradiate the ethylbenzene with UV light , it leads to homolytic cleavage and 1- Phenyl ethyl free radical is generated.
Phenyl ethyl free radical is generated because it is very stable as it is on a secondary carbon center as well as on a benzylic position so it can be stabilized by the resonance as well as inductive effect at the secondary carbon center.
NBS(N-bromosuccinimide) is a source of bromine radical and provides bromine free radical.
Once the 1- Phenyl ethyl free radical is generated then bromine free radical can recombine with benzyl free radical leading to product formation.
Since 1- Phenyl ethyl free radical has a trigonal planar geometry so it is a planar molecule which has two faces and hence the radical recombination with bromine free radical can occur with either of the two faces available.
Kindly refer the attachments for structure as well as the mechanism of the reaction.
So two isomers which are enantiomers are produced are obtained.
It says
The majority of elements on the periodic table are ______________ (metals, nonmetals, or metalloids).
The periodic table on the left separates elements into three groups: the metals (green in the table), nonmetals (orange), and metalloids (blue). Most elements are metals.
Apr 18, 2003
Here is an acid-base reaction. Hydrochloric acid (HCl) reacts with strontium hydroxide [ Sr(OH)2 ]
Ions H+ and OH- neutralize each other. If the amounts are not equal, one of them will be in excess.
Follow the steps as
1. Find moles of ions: mole= Molarity * Volume (in liter) ; n= M * V OR millimole = Molarity * Volume (in ml) ;
2. Write the equation
3. Find out excess ion
4. Use final volume (V acid + V base ) to calculate concentration of excess ion.
n HCI = 28 ml * 0.10 M = 0.28 mmol, releases 0.28 mmol H+ ions
n Sr(OH)2= 60 ml * 0.10 M= 0.60 mmol, releases 2* 0.60=1.20 mmol OH- ions
since Sr(OH)2⇒ Sr2+ + 2OH-
Neutralization reaction is OH- + H+ ---> H2O. The ratio is 1:1. That means 1 mmol hydroxide ions will neutralize 1 mmol hydrogen ions. Since OH- ions are greater in amount, they will be in excess
n(OH-) - n(H+)= 1.20 - 0.28 = 0.92 mmol OH- ions UNREACTED.
Total volume= V acid + V base= 28 ml + 60 ml = 98 ml
Molarity of OH- ions= mole / Vtotal = 0.92/98= 0.009 M
The answer is 0.009 M.
Answer : Colloid
Explanation : Any colloid which consist of a solid evenly dispersed in a gas phase can be called as smoke. So, if smoke has to be given a matter of substance then it is can be categorized as a Colloid present in gaseous phase. Smoke is a solid which contains minute particles of dust which is homogeneously dispersed in the air.
