Answer:
Components of crude oil can be separated through a process called <u><em>fractional distillation</em></u>.
Explanation:
Fractional distillation can be described as a method of distillation in which a liquid mixture is separated based on the different boiling points of the components present in the mixture. The components of crude oil have different boiling temperatures hence, they can be separated by the process of fractional distillation.
The fractionating column has high temperatures at the bottom so components with high temperatures are separated at the bottom. The upper columns have lower temperatures. Components with lower boiling temperatures get separated at the upper columns.
The status of the state of matter of a material defines the phase. Pellet currently case 16 is defined; three of which solid, liquid and gas are referred to as conventional cases. There are a total of 16 state currently defined, these classic except; liquid crystal, amorphous solid, magnetic regularly, superconducting, superfluid, the Bose-Einstein condensation, Rydberg molecules, plasma (ionized gas), the quark-gluon plasma, degenerate matter, Superkate, the stringy liquid and SuperCam mine. Daily life in general, solid materials, include liquid or gaseous, but outside world, 99% of the material in the universe plasma (ionized gas) is in the form.
Answer:
12.02 g
Explanation:
From the question given above, the following data were obtained:
Half life (t½) = 2 days
Original amount (N₀) = 96 g
Time (t) = 6 days
Amount remaining (N) =..?
Next, we shall determine the rate of disintegration of the isotope. This can be obtained as follow:
Half life (t½) = 2 days
Decay constant (K) =?
K = 0.693 / t½
K = 0.693 / 2
K = 0.3465 /day
Therefore, the rate of disintegration of the isotope is 0.3465 /day.
Finally, we shall determine the amount of the isotope remaining after 6 days as follow:
Original amount (N₀) = 96 g
Time (t) = 6 days
Decay constant (K) = 0.3465 /day.
Amount remaining (N) =.?
Log (N₀/N) = kt / 2.303
Log (96/N) = (0.3465 × 6) / 2.303
Log (96/N) = 2.079/2.303
Log (96/N) = 0.9027
Take the anti log of 0.9027
96/N = anti log (0.9027)
96/N = 7.99
Cross multiply
96 = N × 7.99
Divide both side by 7.99
N = 96 /7.99
N = 12.02 g
Therefore, the amount of the isotope remaining after 6 days is 12.02 g
