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AnnZ [28]
3 years ago
15

A 28.5 gram piece of iron is added to a graduated cylinder containing 45.5 mL of water. The water in the cylinder rises to the 4

9.1 mark. Calculate the density of the iron piece.
Chemistry
1 answer:
sweet-ann [11.9K]3 years ago
4 0

Answer:

7.92 .g . mL^-1

Explanation:

Data provided in the question

Water liters = 45.5 mL

Pace of iron = 28.5 gram

Rise in the water in the cylinder = 49.1 mark

So by considering the above information

As we know that

Density = \frac{Mass}{Volume}

where,

Mass = 28.5 gram

Volume = 49.1 - 45.5

              = 3.6 mL

So, the density is

Density = \frac{28.5}{3.6}

= 7.92 .g . mL^-1

Basically we use the density formula by dividing the mass with the volume

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<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

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Putting value in the given equation:

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