Answer:
Specific heat of metal of the metal is 0.8394J/g°C
Explanation:
The heat the water gain is the same losing for the metal. The equation is:
m(Metal)*ΔT(Metal)*S(Metal) = m(Water)*ΔT(Water)*S(Water)
<em>Where m is mass: 66.0g water and 28.5g Metal</em>
<em>ΔT is change in temperature: (95.25°C-27.84°C) = 67.41°C for the metal and (27.84°C - 22.00°C) = 5.84°C for the water</em>
<em>And S is specific heat of water (4.184J/g°C) and the metal</em>
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Replacing:
28.5g*67.41°C*S(Metal) = 66.0g*5.84°C*4.184J/g°C
S(Metal) = 0.8394J/g°C
<h3>Specific heat of metal of the metal is 0.8394J/g°C</h3>
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Answer:
It is an example of coupling an exogenic reaction to an endogenic reaction.
Explanation:
The endergonic reaction is typically being pushed by coupling it to strongly exergonic reaction. This is in most cases via shared intermediates. Most chemical reactions are endergonic in nature. In other word, the are not spontaneous (i.e ΔG>0). Energy must also be applied externally to initiate the reactions. The reactions can also be coupled to exergonic reactions (with ΔG<0) to initiate them through a process known as share intermediate. Because Gibbs Energy can be summed up (i.e is a state function), the combined ΔG of the coupled reaction will be thermodynamically favorable. The decomposition of calcium carbonate is a typical example.
50.00ml*(10^-3L/ml)*(3.91moles/L) = 0.196 mol
The ans should be C. ( if i'm not wrong )
This is because the solubility of oxygen increases when temperature in the water is cooler. Cold water can hold more dissolved oxygen than warm water, thus having a higher concentration of oxygen.
It's K since K and Na are in the same family
