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enot [183]
3 years ago
11

How do you measure the volume of a rubber duck?

Chemistry
2 answers:
EleoNora [17]3 years ago
8 0

Answer:

Im sorry i though this was a joke i don't know I'm sorry:

babymother [125]3 years ago
8 0
<h2>Answer:</h2>

\huge\boxed{Buoyant Force}

<h2>_____________________________________</h2><h2>ARCHEMEDIS LAW (EUREKA) </h2>

A body at rest in a fluid is acted upon by a force pushing upward called the buoyant force, which is equal to the weight of the fluid that the body displaces. If the body is completely submerged, the volume of fluid displaced is equal to the volume of the body. That is how we find the Volume of the Irregularly shaped objects.

<h2>_____________________________________</h2><h2>FUN FACT:</h2>

Archemedes the GREAT GREEK PHYSICIST was in a real problem finding out the formula of how to find the volume of irregular object. After countless failures in finding it, once he was going to get a apparently "BUBBLE BATH", So when he got into the tub the water displaced and got out from the tub resulting in the splash of water. His MIND CLICKED that we could find the volume by submerging the irregular object into the measured water and then substract the displaced water from it. He ran NAKED out of the house because of the happiness saying EUREKA! EUREKA! which literally means "I have found it". Thus this law of Archemedes is also called EUREKA LAW. So to simply remember how to find volume of irregular object keep EUREKA in mind.

<h2>_____________________________________</h2>

Best Regards,

<h3> "BORZ"</h3><h2 /><h2 /><h2 /><h2 /><h2 />
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CO2(g)+CCl4(g)⇌2COCl2(g) Calculate ΔG for this reaction at 25 ∘C under these conditions: PCO2PCCl4PCOCl2===0.140 atm0.185 atm0.7
padilas [110]

<u>Answer:</u> The \Delta G for the reaction is 54.425 kJ/mol

<u>Explanation:</u>

For the given balanced chemical equation:

CO_2(g)+CCl_4(g)\rightleftharpoons 2COCl_2(g)

We are given:

\Delta G^o_f_{CO_2}=-394.4kJ/mol\\\Delta G^o_f_{CCl_4}=-62.3kJ/mol\\\Delta G^o_f_{COCl_2}=-204.9kJ/mol

To calculate \Delta G^o_{rxn} for the reaction, we use the equation:

\Delta G^o_{rxn}=\sum [n\times \Delta G_f(product)]-\sum [n\times \Delta G_f(reactant)]

For the given equation:

\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(COCl_2)})]-[(1\times \Delta G^o_f_{(CO_2)})+(1\times \Delta G^o_f_{(CCl_4)})]

Putting values in above equation, we get:

\Delta G^o_{rxn}=[(2\times (-204.9))-((1\times (-394.4))+(1\times (-62.3)))]\\\Delta G^o_{rxn}=46.9kJ=46900J

Conversion factor used = 1 kJ = 1000 J

The expression of K_p for the given reaction:

K_p=\frac{(p_{COCl_2})^2}{p_{CO_2}\times p_{CCl_4}}

We are given:

p_{COCl_2}=0.735atm\\p_{CO_2}=0.140atm\\p_{CCl_4}=0.185atm

Putting values in above equation, we get:

K_p=\frac{(0.735)^2}{0.410\times 0.185}\\\\K_p=20.85

To calculate the gibbs free energy of the reaction, we use the equation:

\Delta G=\Delta G^o+RT\ln K_p

where,

\Delta G = Gibbs' free energy of the reaction = ?

\Delta G^o = Standard gibbs' free energy change of the reaction = 46900 J

R = Gas constant = 8.314J/K mol

T = Temperature = 25^oC=[25+273]K=298K

K_p = equilibrium constant in terms of partial pressure = 20.85

Putting values in above equation, we get:

\Delta G=46900J+(8.314J/K.mol\times 298K\times \ln(20.85))\\\\\Delta G=54425.26J/mol=54.425kJ/mol

Hence, the \Delta G for the reaction is 54.425 kJ/mol

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The correct answer is - 1 cm/yr.

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1,000 x 10,000 = 10,000,000

1,000 km = 10,000,000 cm

Than we need to divide the number of cm with the number of years:

10,000,000 / 10,000,000 = 1

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