All categories

3 years ago

Find P(1), if p(x)=(x-1) (x+1)

Mathematics

2 answers:

Mkey [24]3 years ago

8 0

Answer:

Step-by-step explanation:

So we have the function:

$p(x)=(x-1)(x+1)$

To find p(1), substitute x for 1:

$p(1)=((1)-1)((1)+1)\\$

Simplify:

$p(1)=(0)(2)\\p(1)=0$

Thus, p(1) is 0.

krok68 [10]3 years ago

8 0

THE ANSWER WOULD BE ZERO

You might be interested in

The results of a survey are shown below. In the survey, 12 students said that they would like to learn French. How many of the s

Ivenika [448]

Answer:

Step-by-step explanation:

24 divided by 12 is 2. 36 divided by 2 is 18.

Hope this is right.

7 0

3 years ago

Read 2 more answers

Please help me!!!!!!!!

Bezzdna [24]

Answer:

(3·x + 6) + (7·x + 4) = 180 --> x = 17

3·17 + 6 = 57

Answer D is correct.

3 0

3 years ago

X plus 1/3 equals nine enter your answer in the box in simplest form

LekaFEV [45]

$= > x + \frac{1}{3} = 9$

$\text{Add} \: - \frac{1}{3} \: \text{ on both sides ,}$

$= > x + \frac{1}{3} - \frac{1}{3} = 9 - \frac{1}{3} \\ \\ \\ \\ = > x = \frac{(9 \times 3) - 1}{3} \\ \\ \\ \\ = > x = \frac{27 - 1}{3} \\ \\ \\ \boxed{ \bold{= > x = \frac{26}{3} }} \\ \\ \\ or , \boxed{ \bold{ \: x = 8. \bar{6}}}$

Hence,

$Value \: \: \: of \: \: x \: \: is \: \frac{26}{3} \: \: \: or \: \: \: 8. \bar{6}$

5 0

2 years ago

Write the equation in function form. Show your steps. <br> 2x-3y=0

skad [1K]

Answer: Heyaa!

Your Answer is... \frac{3y}{2}

Step-by-step explanation:

Substitute the value of the variable into the equation and simplify.

Hopefully this helps <em>you !</em>

<em />

- Matthew ~

8 0

2 years ago

Please help me !

miv72 [106K]

List out the multiples of 8

8, 16, 24, 32, 40, 48, 56, 64, 72, 80

I'm going to highlight in bold the values between 20 and 50

8, 16, 24, 32, 40, 48, 56, 64, 72, 80

So the favorable outcomes, aka the outcomes we want, are: {24, 32, 40, 48}

These four values are all divisible by 8. Also, these values are between 20 and 50.

7 0

2 years ago

Find P(1), if p(x)=(x-1) (x+1)​

Find P(1), if p(x)=(x-1) (x+1)