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yulyashka [42]
4 years ago
11

At electrostatic equilibrium, the electric field is zero everywhere inside a conductor, and any charge can only be distributed o

n the surface of the conductor.
a. True
b. False
Physics
1 answer:
Vika [28.1K]4 years ago
4 0

Answer:True

Explanation:

By applying Gauss  law Electric field is zero everywhere  inside the conductor.

According to Gauss law the net flux of an electric field in a closed surface is directly proportional to the enclosed electric charge.  

For example

For a Gaussian surface inside a conductor all the points have zero electric field as the system is in equilibrium. This implies net flux is zero and net charge inside is zero . So all the charge must be at surface on conductor.          

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When an object of mass m1 is hung on a vertical spring and set into vertical simple harmonic motion, its frequency is 12Hz. When
anzhelika [568]

Answer:

Explanation:

Given

When m_1 mass is attached to the spring its frequency is f_1=12\ Hz

when another mass m_2 is attached to m_1 , frequency changes to f_2=4\ Hz

frequency of spring mass system is given by

f=\frac{1}{2\pi }\sqrt{\frac{k}{m}}

for m_1

f_1=\frac{1}{2\pi }\sqrt{\frac{k}{m_1}}

12=\frac{1}{2\pi }\sqrt{\frac{k}{m_1}}-----1

for m_1 and m_2

f_2=\frac{1}{2\pi }\sqrt{\frac{k}{m_1+m_2}}

4=\frac{1}{2\pi }\sqrt{\frac{k}{m_1+m_2}}----2

divide 1 and 2

3=\sqrt{\frac{m_1+m_2}{m_1}}

squaring

9=1+\frac{m_2}{m_1}

\frac{m_2}{m_1}=8

   

8 0
3 years ago
By what factor must we increase the amplitude of vibration of an object at the end of a spring in order to double its maximum sp
strojnjashka [21]

Answer:

A'=2A

Explanation:

According to the law of conservation of energy, the total energy of the system can be expresed as the sum of the potential energy and kinetic energy:

E=U+K=\frac{kA^2}{2}\\E=\frac{kx^2}{2}+\frac{mv^2}{2}=\frac{kA^2}{2}

When the spring is in its equilibrium position, that is x=0, the object speed its maximum. So, we have:

\frac{k(0)^2}{2}+\frac{mv_{max}^2}{2}=\frac{kA^2}{2}\\A^2=\frac{mv_{max}^2}{k}\\A=\sqrt{\frac{mv_{max}^2}{k}}

In order to double its maximum speed, that is v'{max}=2v_{max}. We have:

A'=\sqrt{\frac{m(v'_{max})^2}{k}}\\A'=\sqrt{\frac{m(2v_{max})^2}{k}}\\A'=\sqrt{\frac{4mv_{max}^2}{k}}\\A'=2\sqrt{\frac{mv_{max}^2}{k}}\\A'=2A

6 0
3 years ago
If an electric wire is allowed to produce a magnetic field no larger than that of the Earth (0.55 x 10-4 T) at a distance of 25
antiseptic1488 [7]

we are given in the problem the following dimensions or specifications 
B = 0.000055 T r = 0.25 m constant mu0 = 4*pi*10-7 

The formula that is applicable from physics is 
B = mu0*I/(2*pi*r) I = 2*B*pi*r/mu0 I = 68.75 Amperes 
7 0
3 years ago
Read 2 more answers
What is the mass of an object traveling at 20 m/s with a kinetic energy of 4000 J?<br>​
valentinak56 [21]

Answer:

20 kg

Explanation:

Kinetic energy=½*Mass * velocity²

4000= ½* m*20²

8000=400m

m=8000/400

m=20 kg

5 0
3 years ago
In experimental design: What are<br> the two groups?
sp2606 [1]

Answer:

The correct answer is : a special type of experimental design where subject divides in two groups according their treatment setting.

Explanation:

A two group is a experimental design two groups are the two different groups of subjects divided by the researcher for comparing the data and result to establish relation in variables.

In normal case, one of the two groups one is a group of subjects who get treatment known as experiment or treatment group while other group is known as control group without treatment.

Thus, the correct answer is : a special type of experimental design where subject divides in two groups according their treatment setting.

7 0
3 years ago
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