Ultraviolet light with a wavelength shorter than visible light and a higher radiant energy than visible light.
The shorter the wavelength, the higher the frequency and energy.
Answer
Given,
refractive index of film, n = 1.6
refractive index of air, n' = 1
angle of incidence, i = 35°
angle of refraction, r = ?
Using Snell's law
n' sin i = n sin r
1 x sin 35° = 1.6 x sin r
r = 21°
Angle of refraction is equal to 21°.
Now,
distance at which refractive angle comes out
d = 2.5 mm
α be the angle with horizontal surface and incident ray.
α = 90°-21° = 69°
t be the thickness of the film.
So,


t = 2.26 mm
Hence, the thickness of the film is equal to 2.26 mm.
Maybe because all of them come from natural elements (sun, air and water)
Answer:
The object distance is 92 cm.
Explanation:
let v be the image distance and h be the height of the image, let u the be the object distance and H be the height of the object.
then, the magification of the mirror is given by:
m = -v/u and m = h/H
so, -v/u = h/H
u = -v×H/h
= -(-4.6)×(82)/(4.1)
= 92 cm
Therefore, the object distance is 92 cm.
D is not a scientific experiment.