The percent error associated with Jason’s measurement is 0.596%.
HOW TO CALCULATE PERCENTAGE ERROR:
- The percentage error of a measurement can be calculated by following the following process:
- Find the difference between the true value and the measured value of a quantity.
- Then, divide by the true value and then multiplied by 100
- The true value of the density of iron is 7.874 g/mL
- Jason observed value is 7.921 g/mL
Difference = 7.921 g/mL - 7.874 g/mL
Difference = 0.047 g/mL
Percentage error = 0.047/7.874 × 100
Percentage error = 0.596%.
Therefore, the percent error associated with Jason’s measurement is 0.596%.
Learn more: brainly.com/question/18074661?referrer=searchResults
Answer:A
Explanation:
Because the water at first was not cold or warm and you want to warm it up and it’s gonna obviously be on a bowl so the taste of the bowl has a type of chemical and when you boil the water it is going to go to absorb
the water
Answer:
oxidation occurs at the cathode.
Explanation:
In a voltaic cell electrons move from anode to cathode. At the anode, species give up electrons. This is an oxidation reaction depicted by the oxidation half equation. At the cathode, species accept electrons and become reduced. This is depicted by the reduction half equation. In summary; in a Voltaic cell, oxidation occurs at the anode while reduction occurs at the cathode.
NaOH or sodium hydroxide is a base which reacts with HCl or Hydrochloric acid to from a salt and water. The equation that represents this reaction is as follows: NaOH (I) + HCl (l) ==H2O (l) +NaCl (aq). The reaction between an acid and a base always produces a salt and water. In this case the salt is sodium chloride.
According to Osmotic pressure equation:
π = i M R T
When π =0.307 atm & M = 0.01 mol & R (constant)= 0.0821 L-atom/mol-K &
T= 22+273 = 295 Kelvin
So Van't half vector i = π / (MRT)
= 0.307 / (0.01 * 0.0821 * 295)
= 1.27
When there is no dissociation, i = no. of moles of Hf in 1 L of solution = (1-X)
and when there is a complete dissociation so it is equal 2X according to this equation
HF(aq) + H2O (L) ⇆ H3O (aq) + F (aq)
(1-X) X X
∴ i = (1-X) + (2x)
1.27 = 1+X
∴X= 1.27 - 1 = 0.27
∴ the percent ionization of the acid X = 27 %