1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
murzikaleks [220]
3 years ago
12

1. john needs to create a buffered solution at a ph of 3.5 for his biomedical laboratory

Chemistry
1 answer:
Lunna [17]3 years ago
6 0

Answer:

Use a ratio of 0.44 mol lactate to 1 mol of lactic acid  

Explanation:

John could prepare a lactate buffer.

He can use the Henderson-Hasselbalch equation to find the acid/base ratio for the buffer.

\text{pH} = \text{pK}_{\text{a}} + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}\\\\3.5 = 3.86 + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}\\\\\log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}} = 3.5 - 3.86 = -0.36\\\\\dfrac{\text{[A$^{-}$]}}{\text{[HA]}} = 10^{-0.36} = \mathbf{0.44}

He should use a ratio of 0.44 mol lactate to 1 mol of lactic acid.

For example, he could mix equal volumes of 0.044 mol·L⁻¹ lactate and 0.1 mol·L⁻¹ lactic acid.

You might be interested in
Octane (C8H18) is a component of gasoline that burns
MatroZZZ [7]

Answer:

hold on this will take me awhile

Explanation:

4 0
3 years ago
Solve the quadratic equation 2x^2+13x=15 by method of completing the square<br>​
mafiozo [28]

Answer:

x = 1, -7.5

Explanation:

2x² + 13x = 15

Divide the left side of the equation by 2

2(x² + 6.5x) = 15

Divide 6.5 by 2 and square the quotient

6.5/2 = 3.25

3.25² = 10.5625

Add 10.5625 to the left side

2(x² + 6.5x + 10.5625) = 15

Since you have a 2 outside the parentheses, you will be adding 10.5625•2 to the right side.

10.5625 • 2 = 21.125

2(x² + 6.5x + 10.5625) = 36.125

To factor (x² + 6.5x + 10.5625), add b/2 to x

b/2 = 6.5/2 = 3.25

2(x + 3.25)² = 36.125

Divide by 2

(x + 3.25)² = 18.0625

Square root.

(x + 3.25) = √18.0625

x + 3.25 = ±4.25

Subtract 3.25.

x = 4.25 - 3.25 = 1

x = -4.25 - 3.25 = -7.5

x = 1, -7.5

4 0
3 years ago
X^2/2x^5=2<br><br>how do you solve this ?
Natasha2012 [34]

Answer:

x=\sqrt[3]{\frac{1}{4}}

Explanation:

\displaystyle\frac{x^2}{2x^5}=2\\\\x^2=4x^5\\\\1=4x^3\\\\x^3=\frac{1}{4}\\\\\\x=\sqrt[3]{\frac{1}{4}}

8 0
3 years ago
What does Earth's hydrosphere include? the water on Earth the hard outer part of Earth the layer of gases surrounding Earth the
Makovka662 [10]

It includes all the water on earth.

7 0
4 years ago
Read 2 more answers
Explain why the first ionisation energy of krypton is greater then the first ionisation energy of bromine
MrMuchimi

Answer:

Kr has one more electron than br and so, the nuclear charge increase, which means the nuclear attraction between the nucleus and outer most electron will increase and so will be harder to remove the electron from Kr than Br, so Kr has higher 1st ionisation.

Mark me brainliest!

God bless!

3 0
3 years ago
Other questions:
  • Is it possible for two different materials to have different solubilities
    11·1 answer
  • Why does a bouncing ball rise to a lower height with each bounce
    10·1 answer
  • Find the number of moles of water that can be formed if you have 226 mol of hydrogen gas and 108 mol of oxygen gas.
    14·1 answer
  • Karen has a mass of 53 kg as she rides the up escalator at woodley park station of the washington
    7·1 answer
  • An atom of helium-4 differs from an atom of lithium-7 in that the atom of helium-4 has?
    14·1 answer
  • How many electrons are there in the only energy level of helium, a noble gas? * Two Three Six Eight​
    9·1 answer
  • How many more times intense is an earthquake that measures 8 on the Richter scale than an earthquake that measures 5? Explain yo
    15·2 answers
  • What type of reaction is <br> CuO + H2SO4 ➡️ CuSO4 + H2O
    7·1 answer
  • Which would increase the rate of dissolving salt into water?
    15·1 answer
  • The reaction of iron (III) oxide with carbon monoxide produces iron and carbon dioxide.
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!