A) Ca(OH)2 + CO2 —> CaCO3 + H2O
B) when Ca(OH)2 is reacted with CO2, the CaCO3 produced is a precipitate which turns the solution milky
Based on the bond energies given, the enthalpy change for the reaction of is -33 kJ and the reaction is exothermic.
<h3>What is the change in bond energy of a reaction?</h3>
The change in bond energy of a reaction is calculated using the formula below:
- change in bond energy = sum of energies of bonds broken - sum of energies of bonds formed
A reaction is exothermic if the change in bond energy is negative.
A reaction is endothermic if the change in bond energy is positive.
Given the bond enery values above:
sum of energies of bonds broken = 4 × C-H + Br-Br
sum of energies of bonds broken = 4 × 413 + 193 = 1845 kJ
sum of energies of bonds formed = 3 × C-H + C-Br + H-Br
sum of energies of bonds formed = 3 × 413 + 276 + 363 = 1878 kJ
Thus;
change in bond energy = 1845 - 1878 = -33 kJ
- The reaction is exothermic because the change in bond energy is negative.
Therefore, the enthalpy change for the reaction of is -33 kJ and the reaction is exothermic.
Learn more about enthalpy change at: brainly.com/question/11628413
Δt=
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Because ΔΦ= ABcosθ for each of the N loops and cosθ is just 1 here only A needs to be replaced, and it can be replaced with A=πr^2, which makes that part of the equation ΔΦ_m=N*B0*πa^2
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