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bogdanovich [222]
2 years ago
14

if during the interaction of 36.5 g of hydrochloric acid with magnesium 137 kg of joules energy are released, how much energy wo

uld be released if 96 g of magnesium acted​
Chemistry
1 answer:
svetoff [14.1K]2 years ago
7 0

Explanation:

ANSWER

The molarity =

molecularweight

density×purity×10

=

36.5

1.18×36.5×10

=11.8molar

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Wh
sergey [27]

The correct option would be 3.

Only thermal energy changes


Hope this helps you

Brainliest would be appreciated

-AaronWiseIsBae

5 0
3 years ago
Read 2 more answers
Could someone help me with all of these questions. Also plz if you don't know the answer plz don't put something that isn't righ
densk [106]
Q3.) acidic
q4.)that the solution is acidic
q5.)that the solution is alkaline
3 0
3 years ago
Example: Make 100 mL 0.05 M NaOH from a 1.5 M solution.<br>0.05 * 100 = 1.5 * ?​
____ [38]

Answer:

3.33

Explanation:

M= 0.05*100/1.5= 3.33

4 0
3 years ago
Help! please! hurry! I will mark brainliest if you get it correct!! NO SPAM!!!!!!
Troyanec [42]

Answer: 5.747 * 10^14 Hz

Explanation:

Convert 522nm to m = 522 * 10^-9 m (since 1nm=10^-9m)

If c = wavelength * frequency, where c is the speed of light (3.0 * 10^8 m/s), then you can manipulate the equation to solve for frequency (f).

f = c / wavelength

Plug in the given numbers:

f = (3.0 * 10^8) / (10^-9)

f = 5.747 * 10^14 Hz

4 0
2 years ago
Read 2 more answers
In the reaction FeCl2 + 2NaOH -&gt;Fe(OH)2(s) + 2NaCl, if 6 moles of FeCl2 are added to 6 moles of Na0H, how many moles of NaOH
pogonyaev

Answer : The correct option is, (B) 6 mole

Explanation :

Given moles of FeCl_2 = 6 moles

Given moles of NaOH = 6 moles

First we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

FeCl_2+2NaOH\rightarrow Fe(OH)_2+2NaCl

From the given balanced reaction, we conclude that

As, 1 moles of FeCl_2 react with 2 moles of NaOH

So, 6 moles of FeCl_2 react with \frac{2}{1}\times 6=12 moles of NaOH

From this we conclude that, FeCl_2 is an excess reagent and NaOH is a limiting reagent because the given moles are less than the required moles and it limits the formation of product.

Thus, the number of moles of NaOH used up in the reaction = Required moles of NaOH - Given moles of NaOH

The number of moles of NaOH used up in the reaction = 12 - 6 = 6 moles

Therefore, the number of moles of NaOH used up in the reaction will be, 60 moles

4 0
3 years ago
Read 2 more answers
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