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prisoha [69]
3 years ago
8

According to the concept of length contraction, what happens to the length of an object as it approaches the speed of ligh and t

hen slows down, eventually coming to a stop? O It is always observed as contracting It is always observed as the same length O It is observed as expanding and then contracting back to its original length O It is observed as contracting and then expanding back to its original length
Physics
2 answers:
alexgriva [62]3 years ago
6 0

Answer:

When an object moves its length contracts in the direction of motion. The faster it moves the shorter it gets in the direction of motion. The object in this question moves and then stops moving. So it's length first contracts and then expands to its original length when the motion stops. The speed doesn't have to be anywhere near the speed of light. When the object moves its length contracts no matter how fast or slow it's moving.

Explanation:

vladimir1956 [14]3 years ago
6 0

Answer:

When an object moves its length contracts in the direction of motion. The faster it moves the shorter it gets in the direction of motion. The object in this question moves and then stops moving. So it's length first contracts and then expands to its original length when the motion stops. The speed doesn't have to be anywhere near the speed of light. When the object moves its length contracts no matter how fast or slow it's moving.

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A small metal ball with a mass of m = 62.0 g is attached to a string of length l = 1.85 m. It is held at an angle of θ = 48.5° w
notka56 [123]

The distance x will the ball land after flies off with a horizontal initial velocity  is 3.0635 m.

<h3>What is mechanical energy?</h3>

The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

A small metal ball with a mass of m = 62.0 g is attached to a string of length l = 1.85 m. It is held at an angle of θ = 48.5° with respect to the vertical.

The ball is then released. When the rope is vertical, the ball collides head-on and perfectly elastically with an identical ball originally at rest. This second ball flies off with a horizontal initial velocity from a height of h = 3.76 m, and then later it hits the ground.

The conservation of energy principle states that total mechanical energy remains conserved in all situations where there is no external force acting on the system.

Kinetic energy  = Potential energy

1/2 mv² =mgh₁

The velocity at the bottom, when the height h = 5m, is

v= √2gh₁...................(1)

The vertical height h₁ = l- lcosθ

h₁ = l- lcosθ

h₁ = 1.85 - 1.85cos48.5°

h₁ =0.6241 m

Putting the values in equation (1), we get

v = √2x 9.81 x0.6241

v = 3.499 m/s

The horizontal distance traveled is

x = vt

x = v x √2h/g

Plug the values, we get

x =  3.499 x √2x3.76 / 9.81

x = 3.0635 m

Thus, the horizontal distance ball travels is  3.0635 m.

Learn more about mechanical energy.

brainly.com/question/13552918

#SPJ1

6 0
2 years ago
Can someone see if it's right? thank you. ​
bearhunter [10]

Answer:

it's right you did a great job

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Extensional stress. is your answer.
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Read 2 more answers
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