The projectile (ball) reaches an instantaneous vertical speed (Vy) of zero at maximum height.
so, V(max height) = ¬Г(Vx)^2+(Vy)^2
in this case V(max height) = Vx, where Vy=0
The maximum height, Yf, can be solved using Vfy^2=Viy^2 + 2gy. At maximum height Vfy=0.
Field strength = (15 V) / (4 cm)
Field strength = (15 V) / (0.04 meter)
Field strength = (15/0.04) (volts/meter)
<em>Field strength = 375 volts/meter </em>
B. <span>much precipitation </span>
You do 1000 divide it by 10 which equals 100 W
