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kumpel [21]
2 years ago
8

(1 point) Unknown resistor in voltage divider Suppose that a power supply is connected across two resistors R1 and R2 that are c

onnected in series. The power supply voltage E, the voltage across the second resistor V2, and the first resistance R1 are all known, but R2 is not known. Find an expression for R2 in terms of E,R1,andV2
Physics
1 answer:
just olya [345]2 years ago
5 0

Answer:

R₂ = V₂R₁/(E + V₂)

Explanation:

By voltage divider, V₂ = ER₂/(R₁ + R₂)

So, cross-multiplying, we have

V₂(R₁ + R₂) = ER₂

expanding the bracket, we have

V₂R₁ + V₂R₂ = ER₂

collecting like terms, we have

V₂R₁ = ER₂ + V₂R₂

factorizing, we have

V₂R₁ = (E + V₂)R₂

dividing through by (E + V₂), we have

R₂ = V₂R₁/(E + V₂)

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Using Gauss's law, calculate the electric field at a point distance s from a long wire bearing uniform charge density. i need he
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Answer:

E = 2k  \frac{\lambda}{ r}

Explanation:

Gauss's law states that the electric flux equals the wax charge between the dielectric permeability.

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tells us that the linear charge density is

            λ = q_ {int} /l

            q_ {int} = l λ

we substitute

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is area of ​​cylinder is

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Consider the three dip1acement vectors A = (3i - 3j) m, B = (i-4j) m, and C = (-2i + 5j) m. Use the component method to determin
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Answer with Explanation:

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B=i-4 j m

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By using the formula \mid r\mid=\sqrt{x^2+y^2}

Direction:\theta=tan^{-1}\frac{y}{x}

By using the formula

Direction of D:\theta=tan^{-1}(\frac{-2}{2})=tan^{-1}(-1)=tan^{-1}(-tan45^{\circ})=-45^{\circ}

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E=-3i+3j-i+4j-2i+5j

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