(1 point) Unknown resistor in voltage divider Suppose that a power supply is connected across two resistors R1 and R2 that are c
1 answer:
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Answer:
E = 2k
Explanation:
Gauss's law states that the electric flux equals the wax charge between the dielectric permeability.
We must define a Gaussian surface that takes advantage of the symmetry of the problem, let's use a cylinder with the faces perpendicular to the line of charge. Therefore the angle between the cylinder side area has the same direction of the electric field which is radial.
Ф = ∫ E . dA = E ∫ dA = q_{int} /ε₀
tells us that the linear charge density is
λ = q_ {int} /l
q_ {int} = l λ
we substitute
E A = l λ /ε₀
is area of cylinder is
A = 2π r l
we substitute
E =
E =
the amount
k = 1 / 4πε₀
E = 2k
Answer with Explanation:
We are given that
A=3i-3j m
B=i-4 j m
C=-2i+5j m
a.
Compare with the vector r=xi+yj
We get x=2 and y=-2
Magnitude= units
By using the formula
Direction:
By using the formula
Direction of D:
b.E=-A-B+C
units
Direction of E=