Answer: Electric field vector is created by an electric force of a charged particle.
Explanation: The direction of the field vector can be determined by applying Coulomb’s Law which explains the electric force between charge particles. If q is positive the force is repulsive, to a test charge ( which is positive always ) and if q is negative the force is attractive to a test charge.
That has to be FALSE.
Without knowing anything about chemistry, I just notice that
neither Hydrochloric acid (HCl) nor water (H₂O) has any Carbon
in it. So in a reaction between them, there's nowhere to get
any Carbon from.
Answer:
∅=2021rad
Explanation:
Coherent light with wavelength 540 nm passes through narrow slits with a separation of 0.370 mm . At a distance from the slits which is large compared to their separation, what is the phase difference (in radians) i the light from the two slits at an angle of 28.0 ∘ from the centerline?
A wave is a disturbance which travels through a medium, it transfers energy without a permanent displacement of the medium itself. this is an example of light wave
using the formula below
∅=
the phase difference is given from the above
d= distance/separation of slits .00037m
=wavelength
540*10^-9m
=angle of two slits 28.0 ∘
∅=(
∅=2021rad
there are large bright fringes from the centre line
Answer:
a.) 490m
b.) 98m/s
Explanation:
Given that the
Acceleration g = 9.8 m/s^2
Time = 10s
Since the parachutist jumps out of an aeroplane. The parachutist jumped out from rest. Initial velocity U is therefore equal to zero. That is,
U = 0
Distance covered = height H
The height can be calculated by using second equation of motion
H = Ut + 1/2gt^2
Substitute g and t into the formula
H = 1/2 × 9.8 × 10^2
H = 490 m
Therefore, she travels as far as 490 m
b.) Her final velocity can be calculated by using third equation of motion
V^2 = U^2 + 2gH
Substitute g and H into the formula.
Remember that U = 0
V^2 = 2 × 9.8 × 490
V^2 = 9604
V = sqrt (9604)
V = 98 m/s
Therefore, her final velocity is 98 m/s
Answer:

Explanation:
Equation of the rocket is,

Here, v' is the relative velocity of rocket.
In space F is zero.
So,

Now the momentum can be obtained by multiply by m on both sides.

Now for maxima, 

Now,

Therefore, the mass of the rocket while having maximum momentum is 