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Bad White [126]
3 years ago
11

Which is the correct order of events at a power plant?

Physics
2 answers:
Sveta_85 [38]3 years ago
7 0
The correct answer to the question is A.
This is because each prior step is needed for the next step to happen.
GalinKa [24]3 years ago
4 0
The correct answer is A.

A power station works on the principle of boiling water to create steam, which turns a turbine, generating a potential difference in a transformer with the magnets. The transformer is connected to a circuit, which hence induces a current, generating power.
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A 2.35-kg rock is released from rest at a height of 21.4 m. Ignore air resistance and determine (a) the kinetic energy at 21.4 m
kvasek [131]

Explanation:

Given that,

The mass of rock, m = 2.35-kg

It was released from rest at a height of 21.4 m.

(a) The kinetic energy is given by : E_k=\dfrac{1}{2}mv^2

As the rock was at rest initially, it means, its kinetic energy is equal to 0.

(b) The gravitational potential energy is given by : E_p=mgh

It can be calculated as :

E_p=2.35\times 9.8\times 21.4\\\\E_p=492.84\ J

(c) The mechanical energy is equal to the sum of kinetic and potential energy such that,

M = 0 J + 492.84 J

M = 492.84 J

Hence, this is the required solution.

6 0
3 years ago
If a radio wave carries information by changing the amplitude of the transmitted wave, what kind of broadcast might it possibly
mariarad [96]
Option A because those are the correct ones
4 0
2 years ago
The rotor in a certain electric motor is a flat, rectangular coil with 84 turns of wire and dimensions 2.61 cm by 3.64 cm. The r
ira [324]

Given Information:

Number of turns = N = 84

Area of Rectangular coil = 2.61x3.64 cm = 0.0261x0.0364 m

Magnetic field = B = 0.80 T

Current = I = 10.5 mA = 0.0105 A

Angular speed = ω = 3.54x10³ rev/min

Required Information:

(a) Maximum torque = τmax = ?

(b) Peak output power = Ppeak = ?

(c) Work done = W = ?

(d) Average power = Pavg?

Answer:

(a) Maximum torque = 0.00067 N.m

(b) Peak output power = 0.248 W

(c) Work done = 0.00189 J

(d) Average power = 0.1115 W

Explanation:

(a) The toque τ acting on the rotor is given by,

τ = NIABsin(θ)

Where N is the number of turns, I is the current, A is the area of rectangular coil and B is the magnetic field

A = 0.0261x0.0364

A = 0.00095 m²

The maximum toque τ is achieved when θ = 90°

τmax = NIABsin(90°)

τmax = 84*0.0105*0.00095*0.80*1

τmax = 0.00067 N.m

(b) The peak output power of the motor is given by,

Pmax = τmax*ω

ω = 3.54x10³ x 2π/60

ω = 370.7 rad/sec

Pmax = 0.00067*370.7

Pmax = 0.248 W

(c) The amount of work done by the magnetic field on the rotor in every full revolution is given by

W = 2∫NIABωsin(ωt) dt

W = -2NIABcos(ωt)

Evaluating limits,

W = -2NIABcos(π) - (-2NIABcos(0))

W = 2NIAB + 2NIAB

W = 4NIAB

W = 4*84*0.0105*0.00067*0.80

W = 0.00189 J

(d) Average power of the motor is given by

Pavg = W/t

t = 2π/ω

t = 2π/370.7

t = 0.01694 sec

Pavg = W/t

Pavg = 0.00189/0.01694

Pavg = 0.1115 W

4 0
3 years ago
Two massive particles with identical charge are launched into the uniform field between two plates from the same launch point wi
Svetach [21]
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6 0
3 years ago
radio signals emitted from and received by an airplane have her fruit frequency of 3.00 * 10 to the 12th Hertz and travel at the
Elanso [62]

here we know that the speed of the signal is same as the speed of light

so here we will have

v = 3 \times 10^8 m/s

the altitude of the airplane is given as

h = 1 \times 10^4 m

now we know that time taken by the signal to reach the control tower is given as

t = \frac{d}{v}

now it is given as

t = \frac{1 \times 10^4 }{3 \times 10^8}

t = 3.33 \times 10^{-5} s

so above is the time taken by the signal to reach the control tower

3 0
3 years ago
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