An object that travels around another object in space is called a(n)
2 answers:
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Answer:
Force exerted, F = 1.5 N
Explanation:
It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.
i.e. u = 0
v = 30 m/s
Time taken, t = 0.06 s
Mass of the paper, m = 0.003 kg
We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :
F = 1.5 N
So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.
Answer:
Our estimate not done correctly because the width was unrealistic.
Explanation:
Given that,
Length = 6 m
Width = 0.5 m
We need to calculate the area of rectangular floor
Using formula of area
Where, l = length
w= width
Put the value into the formula
We need to find why this estimate not done correct
Using given data
We can say that,
We assume width was unrealistic.
The length of room is 6 m.
We know that,
So, the length would be 20 feet.
The width of room is 0.5 m.
The width of room would be 1.64 feet.
So, the area will be
Hence, Our estimate not done correctly because the width was unrealistic.