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Lilit [14]
4 years ago
13

An object that travels around another object in space is called a(n)

Physics
2 answers:
HACTEHA [7]4 years ago
3 0
Satellite. think of the moon.

Hope this helps!
Vote me Brainliest!
user100 [1]4 years ago
3 0
It's definitely D, satellite
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A loop is oriented perpendicular (0 deg) to a 0.0817 T magnetic field. The magnetic flux through the loop is 5.90 x 10^-6 Wb. Wh
blondinia [14]

Answer:

area is 7.22×10^-5 m^2

Explanation:

let B be the magnetic field strength, A be the area of the skip the pool.

8 0
3 years ago
The answer<br> May someone please help me out.
Olin [163]

magnesium is an element

7 0
3 years ago
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A piece of charcoal used for cooking is found at the remains of an ancient campsite. A 1.09 kg sample of carbon from the wood ha
fgiga [73]

Answer:

t = 17199 years

Explanation:

given,

mass of sample = 1.09 Kg

Activity of living material   = 15 decays / min /g

Activity of living material   = 15 x 1000 decays /min /kg

Activity of living material per 1.09 kg A = 1.09 x 15 x 1000 decays / min

Activity of after time t is A ' = 2020

half life = 57300 years

desegregation constant

λ = 0.693 / 5700

A'= A e^{-\lambda\ t}

A'= 1.09 \times 15 \times 1000 e^{-\lambda\ t}

2020= 1.09 \times 15 \times 1000 e^{-\dfrac{0.693}{5700}\times t}

0.124=e^{-\dfrac{0.693}{5700}\times t}

taking ln both side

\dfrac{0.693}{5700}\times t = 2.09

t = 17199 years

5 0
3 years ago
During an auto accident, the vehicle’s air bags deploy and slow down the passengers more gently than if they had hit the windshi
Allushta [10]

Answer:

d = 0.38 m

Explanation:

As we know that the person due to the airbag action, comes to a complete stop, in 36 msec or less, and during this time, is decelerated at a constant rate of 60 g, we can find the initial velocity (when airbag starts to work), as follows:

vf = v₀ -a*t  

If vf = 0, we can solve for v₀:

v₀ = a*t = 60*9.8 m/s²*36*10⁻³s = 21.2 m/s

With the values of v₀, a and t, we can find Δx, applying any kinematic equation that relates all of some of these parameters with the displacement.

Just for simplicity, we can use the following equation:

vf^{2} -vo^{2} = 2*a*d

where vf=0, v₀ =21.2 m/s and a= -588 m/s².

Solving for  d:

d = \frac{-vo^{2}}{2*a} = \frac{(21.2m/s)^{2} }{2*588 m/s2} =0.38 m

⇒ d = 0.38 m

5 0
3 years ago
Read 2 more answers
Toon Train is traveling at the speed of 10 m/s at the top of a hill. Five seconds later it reaches the bottom of the hill and is
Naddika [18.5K]

Answer:

the rate of acceleration of the train is 4 m/s²

Explanation:

Given;

initial velocity of the train, u = 10 m/s

change in time of motion, dt = 5 s

final velocity of the train, v = 30 m/s

The rate of acceleration of the train is calculated as;

a = \frac{dv}{dt} = \frac{v-u}{dt} = \frac{30-10}{5} = \frac{20}{5} = 4 \ m/s^2

Therefore, the rate of acceleration of the train is 4 m/s²

5 0
3 years ago
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