The answer will be neutral because the same number of protons and the same number of electrons
Answer:
the density of ordinary (baryonic) matter in the universe
Explanation:
Deuterium detection is of interest because the amount of it may be related to the amount of dark matter in the universe, but precise measurements have been difficult to obtain. Due to the way in which deuterium was created in the Big Bang, an exact measurement of the amount of deuterium would allow scientists to set limits on the models of the great explosion.
Also, an exact measure of deuterium would be an indicator of the cosmic density of barions (ordinary matter), and that density of barions would indicate whether ordinary matter is dark and is found in regions such as black holes, gas clouds or brown dwarfs, or it is bright and can be found in the stars. This information will help scientists who try to understand the very beginning of our universe.
The change in potential energy of the proton is 5.6 x
Joule
<h3>
What is a Uniform Electric Field ?</h3>
A uniform electric field is where the electric field strength is the same at all points in the field. In the uniform field, the force experienced by a charge is the same no matter where it is placed in the field.
Given that a proton moves a distance 10 cm in a uniform electric field of 3.5 kN C, in the direction of the field.
- The distance d = 10 cm = 0.1 m
- Electric field E = 3.5 KN/C
- Proton charge q = 1.6 x
C
The Work done = Fd
but F = Eq
Recall that Electric field E = F/q = V/d
Where V = potential difference.
Let us first calculate the V
E = V/d
V = Ed
Substitute all the parameters into the formula above
V = 3.5 × 10³ × 0.1
V = 350 v
from F/q = V/d
make F the subject of formula and substitute it in work formula
F = Vq/d
W.D = Vq/d x d
W.D = Vq
Substitute all the parameters into the formula above
W.D = 350 x 1.6 x 
W.D = 5.6 x
J
Work done = Energy = Potential Energy
Therefore, the change in potential energy of the proton is 5.6 x
<em> Joule</em>
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Learn more about Electric Field here: brainly.com/question/14372859
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Answer:
The minimum gauge pressure is 0.4969 atm.
Explanation:
Given that,
Density = 1040 kg/m³
Height = 4.94 cm
We need to calculate the pressure
Using formula of pressure

Where,
=density
h = height
Put the value into the formula


Pressure in atmospheres


Hence, The minimum gauge pressure is 0.4969 atm.