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AlladinOne [14]
2 years ago
12

(a)It takes 51

Mathematics
1 answer:
never [62]2 years ago
4 0

a) Given :

51 pounds of seed  can be planted in = 9 acre field.

Per pound of seed = \frac{9 \ acre}{51 \ pounds \ of \ seed}

We can convert 9/51 in simplest fraction by dividing top and bottom by 3.

We get

\frac{9/3}{51/3}=\frac{3}{17}

<h3>Therefore, 3/17 of an acrs can be planted per pound of seed.</h3>

b) $10 amount = 16 pounds of sugar.

$1 amount = 16/10 = 1.6 pounds of sugar.

<h3>Therefore, 1.6 pounds of sugar she got per dollar.</h3>
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This would be any equation whose slope isn’t -1 or 1.

If the slope was -1, the lines would be parallel because the have the same slope.

If the slope was 1, the lines would be perpendicular because 1 is the negative reciprocal of -1.

Any line with any other slope will intersect with y=-x.

Hope this helps!
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2 years ago
The function g(x) = -2x + 3. Compare the slopes and y-intercepts. A. Both the slopes and the y-intercepts are different. B. Both
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Answer:

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1 year ago
Tom knows that in his school 10 out of every 80 students are left-handed. There are 384 students in toms school. How many studen
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C (48)

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3 years ago
Which value of m will create a system of parallel lines with no solution? y=mx-6 8x-4y=12 A coordinate grid with one line labele
nydimaria [60]

Answer:

A system of parallel lines will be created where the two lines will never meet and have no common solution at a value of m = 2

Step-by-step explanation:

The equation of the given line is 8·x - 4·y = 12

Which gives;

8·x- 12= 4·y

y = 2·x - 3

Given that the line passes through the points (0, -3) and (1, -1), we have;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

When (x₁, y₁) = (0. -3) and (x₂, y₂) = (1, -1), we have;

Slope, \, m =\dfrac{(-1)-(-3)}{1-(0)} = 2

y - (-3) = 2×(x - 0)

y = 2·x - 3 which is the equation of the given line

For the lines 8·x - 4·y = 12, which is the sane as y = 2·x - 3 and the line y = m·x  - 6 to have no solution, the slope of the two lines should be equal that is m = 2

Given that the line passes through the point (1.5, 0), we have;

y - 0 = 2×(x - 1.5)  

y = 2·x - 3...................(1)

For the equation, y = m·x  - 6, when m = 2, we have;

y = 2·x  - 6..................(2)

Solving equations (1) and (2) gives;

2·x - 3 = 2·x  - 6, which gives;

2·x - 2·x=  - 3 - 6

0 = 9

Therefore, a system of parallel lines will be created where the two lines will never meet and have no common solution at a value of m = 2.

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