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olga_2 [115]
3 years ago
8

Complete the sentence with the word "element" or "compound." O is a(n) and H202 is a(n)

Physics
1 answer:
Sauron [17]3 years ago
5 0

Answer:

O is an element and H2O2 is a compound.

Explanation:

O is a single element while H2O2 has 2 elements, which makes it a compound.

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A long, straight wire carries a current of 8.60
Kay [80]

First of all, we need to calculate the magnetic field generated by the wire at a distance r=3.90 cm=0.039 m, which is given by:

B=\frac{\mu_0 I}{2 \pi r}

where I=8.60 A is the current. Substituting numbers in the equation, we find

B=\frac{(4 \pi \cdot 10^{-7})(8.6 A)}{2 \pi (0.039 m)}=4.4 \cdot 10^{-5} T

And now we can calculate the force exerted on the electron, which is given by:

F=qvB

where q=1.6 \cdot 10^{-19} C is the charge of the electron and v=5.0 \cdot 10^4 m/s is its speed. Substituting data in the formula, we find

F=(1.6 \cdot 10^{-19}C)(5.00 \cdot 10^4 m/s)(4.4 \cdot 10^{-5} T)=3.5 \cdot 10^{-19} N

6 0
3 years ago
Friction exists only when two objects rub against each other.<br> A.True<br> B.False
Rus_ich [418]
A. True friction is two objects touching each other
4 0
3 years ago
Read 2 more answers
A weather emergency siren is mounted on a tower, 105 m above the ground. On one hand, it would be a good idea to make the siren
Svetradugi [14.3K]

Answer:

Explanation:

101 dB = 10.1 B.

Maximum intensity of sound allowed = 10.1 B

Intensity of sound in terms of W/m² can be found as follows

log (I / I₀) = 10.1

I / I₀ = 10¹⁰°¹

I = I₀ X 10¹⁰°¹

= 10⁻¹² X  10¹⁰°¹

= 10⁻¹°⁹ W/m²

105 m above the ground the this intensity will be 105² times

intensity at source point = 10⁻¹°⁹ x 105²

= 138.79 W/m²

energy of sound from source

= 4π times

= 4 x 3.14 x 138.79

= 1743.28W/m²

To calculate in terms of decibel :

log 1743.28 / 10⁻¹²

= log 1743.28 +12

= 15.24 B

= 152.4 dB .

152.4 dB .

4 0
3 years ago
at maximum extension a bungee cord stores 2.0 X 10^6 J of energy. A 10 kg mass extends the bungee cord 1.3m. what is the maximum
Gnoma [55]

Explanation:

A k E increases While P E Decreases

4 0
2 years ago
Cany anyone teach me how to use the vernier callipers?
luda_lava [24]
Place the object in between the two jaws such that they touch opposite ends of the object making sure the object is held firmly but don’t press too tight. If you need to measure an internal diameter, then insert the upper jaws in to the cavity and open them till they touch the sides. Tighten the locking screw to hold the jaws in position.

Note the position of the vernier scale zero on the main scale. The main scale reading is the division just before where the zero mark of the vernier scale is aligned. So is the zero mark aligns just after the fifth division between 3 and 4 the main scale reading is then 3.5.

The next step is to take the vernier scale reading. To do this find the mark on the vernier scale which lines up perfectly with a mark on the main scale. The vernier reading can then be found by multiplying the least value of the vernier scale with the number of divisions till that mark. For example if the least value is 0.01 mm and the 7thmark of the vernier scale is lined up perfectly then the vernier scale reading is 7 x 0.01 = 0.07.

The final step is to add the main scale and vernier readings to get the final measurement. For example 3.5 + 0.07 = 3.57 mm.

5 0
3 years ago
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