Answer:
a) 126 kgm/s
b) 0 kgm/s
c) 3.9 m/s
Explanation:
To solve this question, we will use the law of conservation of momentum.
Momentum before collision = momentum after collision
m1v1 + m2v2 = (m1 + m2)v, where
m1 = mass of the shopping cart, 21 kg
m2 = mass of the box, 11 kg
v1 = initial velocity of the shopping cart, 6 m/s
v2 = initial velocity of the box, 0 m/s
v = final velocity of the box+cart
a)
Momentum of the shopping cart before collision = P
P = mv
P = 21 * 6
P = 126 kgm/s = c
b)
Momentum of the box before collision
Like in question a above, the momentum of the box is P
P = mv
P = 11 * 0
P = 0 kgm/s = b
c)
Velocity of the combined shopping cart wreckage after collision is
m1v1 + m2v2 = (m1 + m2)v
(21 * 6) + (11 * 0) = (21 + 11)v
126 + 0 = 32v
32v = 126
v = 126/32
v = 3.9375 m/s, on approximating to 1 decimal place, we have 3.9 m/s and option b as the answer.
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