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sertanlavr [38]
2 years ago
14

What are the different ways a person could reduce air pollution and energy consumption?

Physics
1 answer:
son4ous [18]2 years ago
3 0
There are a number of ways one can help reduce air pollution and energy consumption.
1) carpool or take public transport to reduce carbon dioxide emission
2) Use energy efficient lights
3) Avoid wasting energy
4) Run appliances like dishwashers and washing machines only when full
5) Buy electric or hand powered lawn maintenance equipment instead of gasoline ones
6) Invest in solar panels
7) Drive a hybrid car
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When atoms are split, they release energy. this concept applies to
balu736 [363]
This applies to nuclear reactions, specifically nuclear fission.

This huge release of energy has been used in atomic bombs and in the nuclear reactors that generate electricity.
6 0
3 years ago
How does the sun's energy most directly influence precipitation in an area?
topjm [15]
The sun's energy influences climate in various ways. For example the latitudes at the equator receive more energy from the sun and therefore have warmer temperatures, On the other hand the sun's energy influences precipitation in a climate by driving the water cycle which determines precipitation.The sun is what makes the water cycle take place. That is the sun provides energy or heat to the earth; the heat causes liquid and frozen water to evaporate into water vapor gas, which rises high in the sky to form clouds ( precipitation), that in turn give us rain
5 0
3 years ago
The mass of a star is 1.61·1031 kg and its angular velocity is 1.60E-7 rad/s. Find its new angular velocity if the diameter sudd
Tcecarenko [31]

Answer:

ω₂ = 1.9025 x 10⁻⁶ rad/s

Explanation:

given,

mass of star = 1.61 x 10³¹ kg

angular velocity = 1.60 x 10⁻⁷ rad/s

diameter suddenly shrinks = 0.29 x present size

      r₂  = 0.29 r₁

using conservation of angular momentum

I₁ ω₁ = I₂ ω₂

(\dfrac{2}{5}mr_1^2)\omega_1=(\dfrac{2}{5}mr2^2)\omega_2

r_1^2\times \omega_1=r_2^2\times \omega_2

r_1^2\times 1.60\times 10^{-7}=(0.29r_1)^2\times \omega_2

1.60\times 10^{-7}=0.0841\times \omega_2

\omega_2=\dfrac{1.60\times 10^{-7}}{0.0841}

   ω₂ = 1.9025 x 10⁻⁶ rad/s

5 0
3 years ago
A Red Rider bb gun uses the energy in a compressed spring to provide the kinetic energy for propelling a small pellet of mass 0.
Kay [80]

Answer:

a.6.5025 J

b.6.5025 J

Explanation:

We are given that

Mass of pellet,m=0.27 g=0.27\times 10^{-3} kg

1 kg=1000 g

Spring constant,k=1800 N/m

x=8.5 cm=8.5\times 10^{-2} m

1m=100 cm

a.Potential energy stored in the compressed spring  is given by

P.E=\frac{1}{2}kx^2

P.E=\frac{1}{2}(1800)(8.5\times 10^{-2})^2

P.E=6.5025 J

b.By using law of conservation of energy

P.E of spring=K.E of the pellet

K.E of the pellet=6.5025 J

6 0
3 years ago
If you blow up a balloon, tie it off, and release it, it will fall to the ground.
RoseWind [281]

Answer:

carbon dioxide (what you are blowing up the balloon with) is a heavy gas. so when you fill the Balloon with it, the balloon will not float. helium is a light gas and floats. gravity takes another. part in this

8 0
2 years ago
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